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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

91.

આપેલ સુરેખ સમીકરણો 2x + y = m, 2x + ny = 3 માટે m અને n મેળવો તથા નીચેના સ્તંભોમાં યોગ્ય જોડી રચો :

(1)→(R), (2)→(p), (3)→(Q)
(1)→(Q), (2)→(R), (3)→(P)
(1)→(R), (2)→(Q), (3)→(P)
(1)→(Q), (2)→(P), (3)→(R)

92.

જો $bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space open vertical bar table row bold x cell bold sin bold space bold x bold comma end cell cell bold cos bold space bold x end cell row cell bold x to the power of bold 2 end cell cell bold minus bold tanx end cell cell bold minus bold x to the power of bold 2 end cell row cell bold 2 bold x end cell cell bold sin bold 2 bold x end cell cell bold 5 bold x end cell end table close vertical bar bold space bold ત ો bold space bold lim with bold x bold rightwards arrow bold 0 below bold space fraction numerator bold f bold apostrophe bold left parenthesis bold x bold right parenthesis over denominator bold x end fraction bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold space$

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fraction numerator bold f bold apostrophe bold left parenthesis bold x bold right parenthesis over denominator bold x end fraction bold space bold equals bold space open vertical bar table row bold 1 bold cosx cell bold minus bold sinx end cell row bold x cell fraction numerator bold minus bold tanx over denominator bold x end fraction end cell cell bold minus bold x end cell row cell bold 2 bold x end cell cell bold sin bold 2 bold x end cell cell bold 5 bold x end cell end table close vertical bar bold space bold plus bold space open vertical bar table row bold x bold sinx bold cosx row cell bold 2 bold x end cell cell bold minus bold sec to the power of bold 2 bold x end cell cell bold minus bold 2 bold x end cell row bold 2 cell bold 2 fraction numerator bold sin begin display style bold 2 end style begin display style bold x end style over denominator bold 2 bold x end fraction end cell bold 5 end table close vertical bar bold space bold plus bold space open vertical bar table row bold x bold sinx bold cosx row bold x cell fraction numerator bold minus bold tanx over denominator bold x end fraction end cell cell bold minus bold x end cell row bold 2 cell bold 2 bold cos bold 2 bold x end cell bold 5 end table close vertical bar bold lim with bold x bold rightwards arrow bold 0 below bold space fraction numerator bold f bold apostrophe bold left parenthesis bold x bold right parenthesis over denominator bold x end fraction bold space bold minus bold space open vertical bar table row bold 1 bold 1 bold 0 row bold 0 cell bold minus bold 1 end cell bold 0 row bold 0 bold 0 bold 0 end table close vertical bar bold space bold plus bold space open vertical bar table row bold 0 bold 0 bold 1 row bold 0 cell bold minus bold 1 end cell bold 0 row bold 2 bold 2 bold 5 end table close vertical bar bold space bold equals bold space bold 0 bold space bold plus bold 2 bold space bold plus bold space bold 2 bold space bold equals bold space bold 4

93.

આપેલી સમીકરણોની સંહતિ માટે અને λ મેળવો μ તથા નીચેના સ્તંભોમાં યોગ્ય જોડી રચો :

x + 2y + 3z = 6, x + 3y + 5z = 9, 2x + 5y + λz = μ

(1)→(R), (2)→(Q), (3)→(P)
(1)→(P), (2)→(Q), (3)→(R)
(1)→(Q), (2)→(R), (3)→(P)
(1)→(R), (2)→(P), (3)→(Q)

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Gujarati JEE Mathematics : નિશ્વાયક

Multiple Choice Questions

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