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Gujarati JEE Chemistry : પૃષ્ઠરસાયણ

Multiple Choice Questions

41.

30 àª®àª¿àª²àª¿
120 àª®àª¿àª²àª¿
60 àª®àª¿àª²àª¿
90 àª®àª¿àª²àª¿

42.
પૃષ્ઠ ઉદ્દીપનીય પ્રક્રિયાના વેગમાં વધારો કરવા માટે નીચેનામાંથી કયાં પરિબળો જવાબદાર છે. યોગ્ય વિકલ્પ પસંદ કરો.
I. ઉદ્દીપક એ પ્રક્રિયકના અણુઓને પ્રક્રિયા થવા માટેની યોગ્ય દિશા પૂરી પાડે છે.
II. પ્રક્રિયકના અણુઓની અધિશોષણ ઉષ્માના ઉપયોગ દ્વારા ઉદ્દીપક પ્રક્રિયકોના અણુઓની સક્રિયકરણ ઊર્જામાં ઘટાડો કરે છે.
III. ઉદ્દીપક એ પ્રક્રિયાની સક્રિયકરણ ઊર્જામાં વધારો કરે છે.
IV. ઉદ્દીપકની સપાટી ઉપર રહેલાં સક્રિય કન્દ્રો પર થતા અધિશોષણને લીધે પ્રક્રિયક અણુઓની સાંદ્વતામાં વધારો કરે છે.

(I), (II)
(I), (II), (IV)
(II), (IV)
(I), (II), (III)

43. દ્વાવણ માટે લૅંગ્મ્યૂર અધોશોષણ સમતાપીનું સમીકરણ નીચેનામાંથી કયું યોગ્ય છે ?

$straight x over straight m space equals space fraction numerator a c over denominator 1 space plus space b c end fraction$
$straight m over straight x space equals space fraction numerator 1 space plus space b c over denominator a c end fraction$
$straight m over straight x space equals space 1 over K times 1 over C to the power of 1 over n end exponent$
આપેલ પૈકી એક પણ નહી

44. નીચેનામાંથી કઈ પ્રક્રિયાઓ વિષમાંગ ઉદ્દીપન માટેની છે ?
$bold left parenthesis bold I bold right parenthesis bold space bold 2 bold SO subscript bold 2 bold left parenthesis bold g bold right parenthesis end subscript bold space bold plus bold space bold O subscript bold 2 bold left parenthesis bold g bold right parenthesis end subscript bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold NO subscript bold left parenthesis bold g bold right parenthesis end subscript bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space on top bold space bold 2 bold SO subscript bold 3 bold left parenthesis bold s bold right parenthesis end subscript bold left parenthesis bold II bold right parenthesis bold space bold 2 bold SO subscript bold 2 bold left parenthesis bold g bold right parenthesis end subscript bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left square bracket bold Pt subscript bold left parenthesis bold s bold right parenthesis end subscript bold right square bracket bold space bold space bold space bold space bold space bold space bold space bold space on top bold space bold 2 bold SO subscript bold 3 bold left parenthesis bold s bold right parenthesis end subscript bold left parenthesis bold III bold right parenthesis bold space bold N subscript bold 2 bold left parenthesis bold g bold right parenthesis end subscript bold space bold plus bold space bold 3 bold H subscript bold 2 bold left parenthesis bold g bold right parenthesis end subscript bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold space bold space bold space bold left square bracket bold Fe subscript bold left parenthesis bold s bold right parenthesis end subscript bold right square bracket bold space bold space bold space bold space bold space bold space bold space on top bold space bold 2 bold H subscript bold 3 bold left parenthesis bold g bold right parenthesis end subscript bold space bold left parenthesis bold IV bold right parenthesis bold space bold CH subscript bold 3 bold COOCH subscript bold 3 bold left parenthesis bold l bold right parenthesis end subscript bold space bold plus bold space bold H subscript bold 2 bold O subscript bold left parenthesis bold 1 bold right parenthesis end subscript bold space bold rightwards arrow with bold space bold space bold space bold space bold space bold space bold left square bracket bold H to the power of bold plus subscript bold 9 bold aq bold right parenthesis end subscript bold right square bracket bold space bold space bold space bold space bold space bold space bold space on top bold space bold CH subscript bold 3 bold COOH subscript bold left parenthesis bold aq bold right parenthesis end subscript bold space bold plus bold space bold CH subscript bold 3 bold OH subscript bold left parenthesis bold aq bold right parenthesis end subscript$

(II), (III), (IV)
(II), (III)
(IV)
(I), (II), (III)

45.

$straight P left parenthesis straight N subscript 2 right parenthesis space equals space 0.001$ àªµàª¾àª¤àª¾, V = 2.46 àª¸à«‡àª®à«€³ T = 298 K;

R = 82.0 àªµàª¾àª¤àª¾ àª¸à«‡àª®à«€³ àª•^-1.

N₂ àª¨àª¾ àª®à«‹àª² (n) = $PV over RT space equals space fraction numerator 0.001 space cross times space 2.46 over denominator 82.0 space cross times space 298 end fraction space equals space 1.006 space cross times space space 10 to the power of negative 7 end exponent$

àª…àª§àª¿àª¶à«‹àª·àª¿àª¤ àª¥àª¯à«‡àª²àª¾ N₂ àªµàª¾àª¯à«àª¨àª¾ àª…àª£à«àª“àª¨à«€ àª¸àª‚àª–à«àª¯àª¾ = $1.00 space 6 space cross times space 10 to the power of negative 7 end exponent space cross times space 6.022 space cross times space 10 to the power of 23$

= $6.022 space cross times space 10 to the power of 16$

$equals space 6.023 space cross times space 10 to the power of 14 space cross times space 1000 equals space 6.023 space cross times space 10 to the power of 17$

àª¸àªªàª¾àªŸà«€àª¨à«€ àª¬àª¾àªœà«àª“ àªœà«àª¯àª¾àª‚ N₂ àªµàª¾àª¯à« àª…àª§àª¿àª¶à«‹àª·àª¿àª¤ àª¥àª¯à«‡àª²à«‹ àª¹à«‹àª¯ $equals space fraction numerator 6.023 space cross times space 10 to the power of 17 space cross times space 20 over denominator 100 end fraction space equals space 12.046 space cross times space 10 to the power of 16$

N₂ àª…àª£à« àª¦à«àªµàª¾àª°àª¾ àª…àª§àª¿àª¶à«‹àª·àª¿àª¤ àª¬àª¾àªœà«àª“àª¨à«€ àª¸àª‚àª–à«àª¯àª¾ $equals space fraction numerator 12.046 space cross times space 10 to the power of 16 over denominator 6.023 space cross times space 10 to the power of 16 end fraction space equals space 2 space$

$straight P left parenthesis straight N subscript 2 right parenthesis space equals space 0.001$ àªµàª¾àª¤àª¾, V = 2.46 àª¸à«‡àª®à«€³ T = 298 K;

R = 82.0 àªµàª¾àª¤àª¾ àª¸à«‡àª®à«€³ àª•^-1.

= $6.022 space cross times space 10 to the power of 16$

$equals space 6.023 space cross times space 10 to the power of 14 space cross times space 1000 equals space 6.023 space cross times space 10 to the power of 17$

46. ફ્રુન્ડલિચ અધિશોષણ સમતાપી દ્વાવણોને લાગુ પાડવામાં આવે, તો તેના માટે નીચેનામાંથી કયું સમીકરણ લાગુ પડશે ?

$straight m over straight x space equals space fraction numerator 1 space plus space b c over denominator a c end fraction$
$straight m over straight x space equals space 1 over K times C to the power of begin inline style 1 over n end style end exponent$
$straight x over straight m equals fraction numerator a c over denominator 1 space plus space b c end fraction$
$straight x over straight m equals K times C to the power of begin inline style 1 half end style end exponent$