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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

11.

N₂O_4(g) $rightwards arrow$ 2NO_2(g) àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¦àª°àª®àª¿àª¯àª¾àª¨ N₂O₄àª¨à«àª‚ àª¦àª¬àª¾àª£ 30 àª®àª¿àª¨àª¿àªŸàª®àª¾àª‚ 0.3 àªµàª¾àª¤àª¾.àª¥à«€ 0.32 àªµàª¾àª¤àª¾ àª¥àª¾àª¯ àª›à«‡. NO₂ àª¨àª¾ àª‰àª¤à«àªªàª¾àª¦àª¨àª¨à«‹ àªµà«‡àª— àªœàª£àª¾àªµà«‹.

0.012 àªµàª¾àª¤àª¾. àª®àª¿àª¨àª¿àªŸ^-1
0.24 àªµàª¾àª¤àª¾. àª®àª¿àª¨àª¿àªŸ^-1
0.006 àªµàª¾àª¤àª¾. àª®àª¿àª¨àª¿àªŸ^-1
0.003 àªµàª¾àª¤àª¾. àª®àª¿àª¨àª¿àªŸ^-1

12. પ્રક્રિયા H + OH^- $rightwards arrow$ H₂O માં H આયનની સાંદ્વતામાં 0.02Mજેટલો ઘટાડો થતાં બે નેનો સેકન્ડ લાગે છે. પ્રક્રિયાનો સરેરાશ વેગ કેટલો હશે ?

2 Ms^-1
1 × 10⁷ Ms^-1
0.02 × 10⁹ Ms^-1
આપેલ પૈકી એક પણ નહી

13.

àªªà«àª°àª•à«àª°àª¿àª¯àª¾ : $bold 2 bold N subscript bold 2 bold O bold space bold rightwards arrow bold space bold 4 bold NO subscript bold 2 bold space bold plus bold space bold O subscript bold 2 bold space$ àª¨à«àª‚ àªµà«‡àª— àª¸àª®à«€àª•àª°àª£ àª¤à«àª°àª£ àªªà«àª°àª•àª¾àª°à«‡ àª²àª–à«€ àª¶àª•àª¾àª¯ àª›à«‡, àª¤à«‹ K àª…àª¨à«‡ K' àª¤àª¥àª¾ K àª…àª¨à«‡ K'' àªµàªšà«àªšà«‡àª¨à«‹ àª¸àª‚àª¬àª‚àª§ àª•àª¯à«‹ àª›à«‡ ?

fraction numerator bold minus bold d bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket bold space bold space fraction numerator bold d bold left square bracket bold NO subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold apostrophe bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket bold space bold space fraction numerator bold d bold left square bracket bold O subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold K bold apostrophe bold apostrophe bold left square bracket bold N subscript bold 2 bold O subscript bold 5 bold right square bracket

K' = 2K, K'' = 2K
K' = 2K, K'' = K
K' = 2K, K'' = $bold K over bold 2$
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

14.

$bold N subscript bold 2 bold space bold plus bold space bold 3 bold H subscript bold 2 bold space bold rightwards harpoon over leftwards harpoon bold space bold 2 bold NH subscript bold 3 bold space$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª®àª¾àª‚ àª¹àª¾àª‡àª¡à«àª°à«‹àªœàª¨àª¨à«€ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾àª®àª¾àª‚ àª¥àª¤à«‹ àª«à«‡àª°àª«àª¾àª° -0.3 × 10^-4Ms^-1 àª®àª³à«‡ àª›à«‡. àª¤à«‡ àª¸àª®àª¯à«‡ àªàª®à«‹àª¨àª¿àª¯àª¾àª¨à«€ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾àª®àª¾àª‚ àª¥àª¤à«‹ àª«à«‡àª°àª«àª¾àª° = .......... .

0.2 × 10^-4
-0.2 × 10^-4
0.1 × 10^-4
0.3 × 10^-4

15.

àªªà«àª°àª•à«àª°àª¿àª¯àª¾ : BrO₃^-_(aq) + 5Br^-_(aq) + 6H_(aq) $rightwards arrow$ 3Br₂₍₁₎ + 3H₂O₍₁₎ àª®àª¾àª‚ Br^-àª¨àª¾ àªµàªªàª°àª¾àª¶àª¨à«‹ àª¦àª° 1.5 × 10^-2Ms^-1àª›à«‡. H àª¨àª¾ àªµàªªàª°àª¾àª¶àª¨à«‹ àª¦àª° àª…àª¨à«‡ Br₂ àª‰àª¤à«àªªàª¨à«àª¨ àª¥àªµàª¾àª¨à«‹ àª¦àª° àª…àª¨à«àª•à«àª°àª®à«‡ .......... àª¥àª¶à«‡.

(5 × 6) 1.5 × 10^-2, (3 × 6) 1.5 × 10^-2
(5 + 6) 1.5 × 10^-2, (3 + 6) 1.5 × 10^-2
$open parentheses 6 over 5 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent comma space open parentheses 3 over 5 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent$
$open parentheses 5 over 6 close parentheses space 1.5 space cross times space 10 to the power of negative 2 end exponent comma space open parentheses 5 over 3 close parentheses space space 1.5 space cross times space 10 to the power of negative 2 end exponent$

16. H₂ + I₂ ⇌ 2HI $negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator dt end fraction$ પ્રક્રિયા માટે સાચો પ્રક્રિયાવેગ કયો છે ?

$negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator 2 dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator 2 dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator dt end fraction$
$negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator 2 dt end fraction space equals space minus fraction numerator straight d left square bracket straight I subscript 2 right square bracket over denominator 2 dt end fraction space equals space plus space fraction numerator straight d left square bracket HI right square bracket over denominator 4 dt end fraction$
$negative fraction numerator straight d left square bracket straight H subscript 2 right square bracket over denominator dt end fraction space equals space minus fraction numerator 2 straight d left square bracket straight I subscript 2 right square bracket over denominator dt end fraction space equals space plus space fraction numerator 2 straight d left square bracket HI right square bracket over denominator dt end fraction$

17.

àªªà«àª°àª•à«àª°àª¿àª¯àª¾ : A + 2B $rightwards arrow$ C + 2Dàª®àª¾àª‚ t₁ àª¸àª®àª¯à«‡ $bold minus fraction numerator bold d bold left square bracket bold A bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold 2 bold. bold 6 bold space bold cross times bold space bold 10 to the power of bold minus bold 2 end exponent bold M bold space bold sec to the power of bold minus bold 1 end exponent$ àª›à«‡, àª¤à«‹ t₁àª¸àª®àª¯à«‡ $bold minus fraction numerator bold d bold left square bracket bold B bold right square bracket over denominator bold dt end fraction$ ........... àª¥àª¶à«‡.a

1.0 × 10^-1
6.5 × 10^-3
5.2 × 10^-2
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

5.2 × 10^-2

$negative fraction numerator straight d left square bracket straight A right square bracket over denominator dt end fraction space equals space minus 1 half space fraction numerator straight d left square bracket straight B right square bracket over denominator dt end fraction therefore space minus space fraction numerator straight d left square bracket straight B right square bracket over denominator dt end fraction space space space equals space 2 space cross times space minus fraction numerator straight d left square bracket straight A right square bracket over denominator dt end fraction space equals space 2 space cross times space 2.6 space plus space 10 to the power of negative 2 end exponent space straight M space Sec to the power of negative 1 end exponent space space space space space space space space space space space space space space space space space space space space space space equals space space space 5.2 space cross times space 10 to the power of negative 2 end exponent space straight M. space Sec to the power of negative 1 end exponent space$

18. $bold plus bold 1 over bold 3 fraction numerator bold d bold left square bracket bold Br subscript bold 2 bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold space fraction numerator bold d bold left square bracket bold BrO subscript bold 3 to the power of bold minus bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold 1 over bold 5 fraction numerator bold d bold left square bracket bold Br to the power of bold minus bold right square bracket over denominator bold dt end fraction bold space bold equals bold space bold minus bold 1 over bold 6 fraction numerator bold d bold left square bracket bold H to the power of bold plus bold right square bracket over denominator bold dt end fraction bold space$ પ્રક્રિયાવેગ ધરાવતી પ્રક્રિયાનું સંતુલિત સમીકરણ .....

$BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 3 Br subscript 2 left parenthesis aq right parenthesis end subscript$
$BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 3 Br subscript 2 left parenthesis aq right parenthesis end subscript space plus space 3 straight H subscript 2 straight O subscript left parenthesis 1 right parenthesis end subscript$
$Br subscript 2 left parenthesis aq right parenthesis end subscript space plus space BrO subscript 3 to the power of minus subscript left parenthesis aq right parenthesis end subscript space rightwards arrow space 5 Br to the power of minus subscript left parenthesis aq right parenthesis end subscript space plus space 6 straight H subscript left parenthesis aq right parenthesis end subscript$
આપેલ પૈકી એક પણ નહી

19.

bold 2 bold A bold space bold plus bold space bold B bold space bold rightwards arrow bold space bold 2 bold C bold space bold plus bold space bold 2 bold D

માટે નીચેના પૈકી કયું વિધાન ખોટું છે ?

C અને D ઉત્પન્ન થવાનો વેહ સરખો છે.
C ના ઉત્પાદનનોવેગ B ના વપરાશના વેગથી અડધો છે.
B ના વપરાશનો વેગ, A ના વપરાશના વેગથી ચોથા ભાગનો છે.
C ના ઉત્પાદનનો વેગ A ના વપરાશના વેગથી અડધો છે.

20.

$bold 2 bold A bold space bold plus bold space bold B bold space bold rightwards arrow bold space bold 2 bold C bold space bold plus bold space bold 4 bold D$ àª®àª¾àª‚ àª¡ àª¨àª¾ àª‰àª¤à«àªªàª¾àª¦àª¨àª¨à«‹ àªµà«‡àª— 1.6 ×10^-3Ms^-1 àª›à«‡. àª† àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª®àª¾àªŸà«‡ àª¨à«€àªšà«‡àª¨àª¾ àªªà«ˆàª•à«€ àª•àª¯à«àª‚ àªµàª¿àª§àª¾àª¨ àª¸àª¾àªšà«àª‚ àª›à«‡ ?

$negative 1 half fraction numerator straight d left square bracket straight A right square bracket over denominator dt end fraction equals space 1.6 space 10 to the power of negative 3 end exponent Ms to the power of negative 1 end exponent$
$fraction numerator straight d left square bracket straight C right square bracket over denominator dt end fraction equals space 8.0 space cross times 10 to the power of negative 4 end exponent Ms to the power of negative 1 end exponent$
$negative fraction numerator straight d left square bracket straight B right square bracket over denominator dt end fraction space equals space 3.2 space cross times space 10 to the power of negative 3 end exponent Ms to the power of negative 1 end exponent$
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

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Gujarati JEE Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

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