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Gujarati JEE Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

Multiple Choice Questions

71.

0.33 V
-0.33 V
0.037 V
-0.11 V

72.

$bold E to the power of bold 0 subscript bold Cu bold vertical line bold Cu to the power of bold 2 bold plus end exponent end subscript bold space bold equals bold space bold minus bold 0 bold. bold 34 bold space bold V$ àª…àª¨à«‡ $bold E to the power of bold 0 subscript bold Cu to the power of bold 2 bold plus end exponent bold vertical line bold Cu to the power of bold plus end subscript bold space bold equals bold space bold plus bold 0 bold. bold 16 bold space bold V$ àª¹à«‹àª¯, àª¤à«‹ $bold E to the power of bold 0 subscript bold Cu bold vertical line bold Cu to the power of bold plus end subscript$ àª¨à«àª‚ àª®à«‚àª²à«àª¯ àª•à«‡àªŸàª²à«àª‚ àª¥àª¾àª¯ ?

-0.52 V
+0.48 V
-0.48 V
-0.12 V

73.

Co | Co³, CO² | Co³, Fe | Fe³, Fe² | Fe³અર્ધ-કોષના પ્રમાણિત પ્રમાણિત ઑક્સિડેશન- પોટૅન્શિયલ અનુક્રમે -04167 V, -1.81 V, 0.0367 V, -0.77 V છે. તો Fe | Fe² || Co² | Coકોષનો પ્રમાણિત પોટૅન્શિયલ કેટલો થાય ?

1.0 V
-0.11 V
0.16 V
0.72 V

74.

50 $degree$ àª¸à«‡ àª¤àª¾àªªàª®àª¾àª¨à«‡ Ph | H_{2(g.1.0 àª¬àª¾àª°)} | OH^- àª…àª°à«àª§-àª•à«‹àª·àª¨àª¾ E⁰_OXàª¨à«àª‚ àª®à«‚àª²à«àª¯ +0.83 V àª¹à«‹àª¯, àª¤à«‹ 50 $degree$ àª¸à«‡ àª¤àª¾àªªàª®àª¾àª¨à«‡ àªªàª¾àª£à«€àª¨àª¾ àª†àª¯à«‹àª¨à«€àª¯ àª—à«àª£àª¾àª•àª¾àª° (K_W)àª¨à«àª‚ àª®à«‚àª²à«àª¯ àª•à«‡àªŸàª²à«àª‚ àª¥àª¾àª¯ ?

1.105 × 10^-12
1.0 × 10^-14
1.12 × 10^-13
1.102 × 10^-12

1.12 × 10^-13

$50 degree$ àª¸à«‡ àª¤àª¾àªªàª®àª¾àª¨à«‡ Pt/H_2(h.1.0 _{àª¬àª¾àª°)} | $OH subscript left parenthesis aq right parenthesis end subscript superscript minus$ àª…àª°à«àª§àª•à«‹àª·àª¨àª¾ $straight E subscript ox superscript 0$ àª¨à«àª‚ àª®à«‚àª²à«àª¯ + 0.83 V. àª†àªªà«‡àª² àª›à«‡.

Pt/H_2(g.1.0 _{àª¬àª¾àª°)} $OH subscript left parenthesis aq right parenthesis end subscript superscript minus space vertical line vertical line vertical line space straight H subscript left parenthesis aq right parenthesis end subscript superscript plus space vertical line space straight H subscript 2 left parenthesis straight h.1.0 space àª¬ àª¾ àª° right parenthesis end subscript space vertical line space Pt$

àªàª¨à«‹àª¡: $1 half space straight H subscript 2 left parenthesis straight g right parenthesis end subscript space plus space OH subscript left parenthesis aq right parenthesis end subscript superscript minus space vertical line space straight H subscript 2 straight O subscript left parenthesis 1 right parenthesis end subscript space plus space straight e to the power of minus space$

$straight E subscript ax superscript 0 space equals space plus 0.83 space Volt$

$increment straight G to the power of 0 space equals space nF space straight E subscript cell superscript 0 space minus space 2.303 times RT times log space straight K space therefore space log space straight K space equals space fraction numerator nFE subscript cell superscript 0 over denominator 2.303 space RT end fraction$

àª…àª¹à«€àª‚, $straight K space equals space fraction numerator 1 over denominator open square brackets straight H to the power of plus close square brackets open square brackets OH to the power of minus close square brackets end fraction space equals space 1 over straight K subscript straight w$

àª•à«…àª¥à«‹àª¡: $straight H subscript left parenthesis aq right parenthesis end subscript superscript plus space plus space straight e to the power of minus space rightwards harpoon over leftwards harpoon with space space space space space space space space space on top space 1 half space straight H subscript 2 left parenthesis straight g right parenthesis end subscript space straight E subscript red superscript 0 space end superscript space equals space 0.0 straight V space$
àª•à«àª²: $straight H subscript left parenthesis aq right parenthesis end subscript superscript plus space plus space OH subscript left parenthesis aq right parenthesis end subscript superscript minus space rightwards harpoon over leftwards harpoon with space space space space space space space on top space straight H subscript 2 straight O subscript left parenthesis 1 right parenthesis end subscript space straight E subscript cell superscript 0 space equals space plus 0.83 space Volt$

$therefore space log space 1 over straight K subscript straight w space equals space fraction numerator nFE subscript cell superscript 0 over denominator 2.303 space RT end fraction therefore space minus space log space straight K subscript straight w space equals space fraction numerator nFE subscript cell superscript 0 over denominator 2.303 space RT end fraction$

R = 8.314 àªœà«àª²-àª®à«‹àª²^-1. àª•à«…àª²à«àªµàª¿àª¨^-1 $straight F space equals space 96500$ àª•à«àª²àª®à«àª¬/àª®à«‹àª² àª®à«àª•àª¤àª¾àª‚,

$therefore space minus space log space straight K subscript straight w space equals space fraction numerator 4183.13083 over denominator 323 end fraction space equals space 12.9509 therefore space straight K subscript straight w space equals space antilog space left parenthesis negative 12.9509 right parenthesis space equals space Antilog space space space left parenthesis 13 with bar on top.049 right parenthesis space àª†àª¥ à«€ space straight K subscript straight w space equals space 1.12 space cross times cross times space 10 to the power of negative 13 end exponent$

$straight E subscript ax superscript 0 space equals space plus 0.83 space Volt$

75.

25 $degree$ સે તાપમાને Sn | Sn²_{(0.1 M)} || Pb²_{(0.5 M)} | Pb વિદ્યુતરાસાયણિક કોષમાં સંતુલન સ્થપાય ત્યારે ડા.બા.ના અર્ધકોષનો ઑક્સિડેશન પોટૅન્શિયલ કેટલો હશે ? $bold left parenthesis bold E to the power of bold 0 subscript bold Sn to the power of bold 2 bold plus end exponent bold vertical line bold Sn end subscript bold space bold equals bold space bold minus bold 0 bold. bold 14 bold V bold comma bold space bold E to the power of bold 0 subscript bold Pb to the power of bold 2 bold plus end exponent bold vertical line bold Pb end subscript bold space bold equals bold space bold minus bold 0 bold. bold 13 bold space bold V bold right parenthesis$

0.151 V
0.114 V
0.0 V
0.128 V

76.

25 $degree$ àª¸à«‡ àª¤àª¾àªªàª®àª¾àª¨à«‡ $bold Co subscript bold left parenthesis bold s bold right parenthesis end subscript bold space bold plus bold space bold Ni to the power of bold 2 subscript bold left parenthesis bold aq bold space bold 0 bold. bold 1 bold space bold M bold right parenthesis end subscript bold space bold rightwards harpoon over leftwards harpoon bold space bold Co to the power of bold 2 subscript bold left parenthesis bold aq bold space bold 0 bold. bold 01 bold space bold M bold right parenthesis end subscript bold space bold plus bold space bold Ni subscript bold left parenthesis bold s bold right parenthesis end subscript$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾ àª¸àª‚àª¤à«àª²àª¨àª®àª¾àª‚ àª†àªµà«‡, àª¤à«àª¯àª¾àª°à«‡ Ni² àª¨à«€ àª¸àª¾àª‚àª¦à«àªµàª¤àª¾àª®àª¾àª‚ àª•à«‡àªŸàª²àª¾ àªŸàª•àª¾ àª˜àªŸàª¾àª¡à«‹ àª¥àª¯à«‹ àª¹àª¶à«‡ ? $bold left parenthesis bold E to the power of bold 0 subscript bold Co to the power of bold 2 bold plus end exponent bold vertical line bold Co end subscript bold space bold vertical line bold equals bold space bold minus bold 0 bold. bold 28 bold V bold space bold àª…àª¨ à«‡ bold space bold minus bold 0 bold. bold 23 bold space bold V bold right parenthesis$

92.5 %
97.28 %
8.74 %
92.2 %

77.

1.0 × 10^-3 M સાંદ્વતા ધરાવતા Fe³ ના દ્વાવણમાં વધુ પડતો પ્રવાહી પારો ઉમેરવામાં આવે છે. 25 $degree$ સે. તાપમાને 5% Fe³સંતુલન સમયે બાકી રહે છે. જો ફક્ત નીચે દર્શાવેલી પ્રક્રિયા જ શક્ય બનતી હોય, તો $bold E to the power of bold 0 subscript bold Hg to the power of bold 2 bold plus end exponent bold space bold vertical line bold space bold Hg end subscript$ ની કિંમત કઈ હશે ? $bold left parenthesis bold E to the power of bold 0 subscript bold Fe to the power of bold 3 bold vertical line bold Fe to the power of bold 2 bold plus end exponent end subscript bold space bold equals bold space bold 0 bold. bold 77 bold space bold V bold right parenthesis$

$bold 2 bold Hg subscript bold left parenthesis bold 1 bold right parenthesis end subscript bold space bold plus bold space bold 2 bold Fe to the power of bold 3 subscript bold left parenthesis bold aq bold right parenthesis end subscript bold space bold rightwards harpoon over leftwards harpoon bold space bold Hg subscript bold 2 to the power of bold 2 subscript bold left parenthesis bold aq bold right parenthesis end subscript bold space bold plus bold space bold 2 bold Fe to the power of bold 2 subscript bold left parenthesis bold aq bold right parenthesis end subscript$

-0.643 V
-0.793 V
0.793 V
0.634 V

78. Fe | Fe²_{(0.1 M)} || Cd²_{(0.5 M)}| Cd વિદ્યુતરાસાયણિક કોષમાં 298 K તાપમાને સંતુલન સ્થપાય ત્યારે ઍનોડ અને કૅથોડના રિડક્શન પોટૅન્શિયલ મૂલ્યો કેટલાં હશે ? (n = 2) ( $bold E to the power of bold 0 subscript bold Fe to the power of bold 2 bold plus end exponent bold vertical line bold space bold Fe end subscript bold space bold equals bold space bold minus bold 0 bold. bold 44 bold space bold V$ અને $bold E to the power of bold 0 subscript bold Cd to the power of bold 2 bold plus end exponent bold space bold vertical line bold space bold Cd end subscript bold space bold equals bold space bold minus bold 0 bold. bold 40 bold space bold V$ છે.)

-0.575 V
+0.477 V
-0.447 V
-0.477 V

79. 298 K તાપમાને નીચે આપેલા વિદ્યુતરાસાયણિક કોષમાં થતી પ્રક્રિયા સંતુલન સ્થિતિમાં છે, તો કયો વિકલ્પ યોગ્ય છે ?
$bold Zn bold space bold vertical line bold space bold Zn to the power of bold 2 subscript bold left parenthesis bold XM bold right parenthesis end subscript bold space bold vertical line bold vertical line bold space bold Cu to the power of bold 2 subscript bold left parenthesis bold yM bold right parenthesis end subscript bold space bold vertical line bold space bold Cu$

$straight E subscript Zn space vertical line Zn to the power of 2 plus end exponent subscript left parenthesis XM right parenthesis end subscript end subscript space plus space straight E subscript Cu to the power of 2 plus end exponent vertical line end subscript Cu space equals space 0.0 space straight V$
$straight E subscript Zn space vertical line space Zn to the power of 2 plus end exponent subscript left parenthesis XM right parenthesis end subscript end subscript space equals space minus straight E subscript Cu to the power of 2 plus end exponent subscript left parenthesis yM right parenthesis end subscript end subscript space vertical line space Cu$
$straight E subscript Zn space vertical line space Zn to the power of 2 plus end exponent subscript left parenthesis XM right parenthesis end subscript end subscript space equals space minus straight E subscript Cu to the power of 2 plus end exponent subscript blank end subscript space vertical line space Cu$
આપેલ પૈકી કે પણ નહી

80.

298 K તાપમાને Co | Co²_(1.0M) || Ni²_(XM) | Ni કોષમાં થતી પ્રક્રિયા સંતુલનમાં છે, તો x = .......... . $bold E to the power of bold 0 subscript bold Co to the power of bold 2 bold plus end exponent bold vertical line bold Co end subscript bold space bold equals bold space bold minus bold 0 bold. bold 28 bold space bold V bold space bold અન ે bold space bold E to the power of bold 0 subscript bold Ni to the power of bold 2 bold plus end exponent bold vertical line bold Ni end subscript bold space bold equals bold space bold minus bold 0 bold. bold 23 bold space bold V$ છે. (n = 2)

0.5 M
0.02 M
1.02 M
1.0 M

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Gujarati JEE Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

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