n વ્યક્તિઓમાંથી 5 ચોક્કસ તક્તિઓ ન આવે, તે રીતે 80 વ્યક્તિઓને વર્તુળાકાર ટેબલ પર કેટલી રીતે ગોઠવી શકાય ? from Mathematics ક્રમચય અને સંચય
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Gujarati JEE Mathematics : ક્રમચય અને સંચય

Multiple Choice Questions

1. MONDAY શબ્દના અક્ષરોની મદદથી Y ન આવે તે રીતે ચાર અક્ષરના કુલ કેટલા શબ્દો ન બને ?

  • 5

  • 120

  • 24

  • 119

Answer
    • 2. open parentheses table row bold 43 row bold 4 end table close parentheses bold space bold plus bold space bold sum from bold r bold equals bold 1 to bold 5 of bold space open parentheses table row cell bold 48 bold minus bold r end cell row bold 3 end table close parentheses bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold space
    • open parentheses table row bold 48 row bold 4 end table close parentheses
    • open parentheses table row bold 47 row bold 4 end table close parentheses
    • open parentheses table row bold 48 row 5 end table close parentheses
    • open parentheses table row bold 48 row bold 3 end table close parentheses
    Answer
    • 3. mn ભિન્ન વસ્તુઓ n વ્યક્તિઓને સમાન ભાગે ....... રીતે વહેંચી શકાય.
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction bold cross times bold space bold n bold space bold factorial
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold n bold space bold factorial bold space bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction bold space bold cross times bold space bold n bold space bold factorial
    Answer
    • 4. કુલ m + n + p વસ્તુઓનું m, વસ્તુઓ, n વસ્તુઓ અને p વસ્તુઓના ત્રણ ભાગમાં વિભાજન કેટલી રીતે કરી શકાય ?
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p end fraction bold cross times bold space bold 3
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p end fraction bold cross times bold space bold 1 over bold 6
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p end fraction bold cross times bold space bold 3 bold space bold factorial
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p bold space bold factorial end fraction
    Answer
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    5.
    n વ્યક્તિઓમાંથી 5 ચોક્કસ તક્તિઓ ન આવે, તે રીતે 80 વ્યક્તિઓને વર્તુળાકાર ટેબલ પર કેટલી રીતે ગોઠવી શકાય ?
    • open parentheses table row cell bold n bold minus bold 5 end cell row cell bold n bold minus bold 85 end cell end table close parentheses bold space bold 79 bold space bold factorial
    • 1 half space open parentheses table row cell bold n bold minus bold 5 end cell row bold 80 end table close parentheses bold space bold 79 bold space bold factorial
    • bold P presubscript bold left parenthesis bold n bold minus bold 5 bold right parenthesis end presubscript subscript bold 80
    • open parentheses table row cell bold n bold minus bold 5 end cell row bold 80 end table close parentheses bold space bold 80 bold space bold factorial

    A.

    open parentheses table row cell bold n bold minus bold 5 end cell row cell bold n bold minus bold 85 end cell end table close parentheses bold space bold 79 bold space bold factorial

    Tips: -

    અહીં n - 5 વ્યક્તિઓમાંથી 80 વ્યક્તિઓને પસંદ કરીને વર્તુળાકાર ટેબલ પર ગોઠવવાના 

    કુલ પ્રકારની સંખ્યા = open parentheses table row cell bold n bold minus bold 5 end cell row bold 80 end table close parentheses bold space bold left parenthesis bold 80 bold space bold minus bold space bold 1 bold right parenthesis bold space bold factorial bold space bold equals bold space open parentheses table row cell bold n bold minus bold 5 end cell row cell bold n bold minus bold 85 end cell end table close parentheses bold space bold 79 bold space bold factorial
    Answer
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    6. 50 વ્યક્તિઓમાંથી ચોક્કસ વ્યક્તિઓ આવે જ, તે રીતે 30 વ્યક્તિઓની પસંદગી કુલ કેટલી રીતે કરી શકાય ?
    • open parentheses table row bold 46 row bold 26 end table close parentheses
    • open parentheses table row bold 46 row bold 30 end table close parentheses
    • 46 P 26
    • open parentheses table row bold 46 row bold 26 end table close parentheses
    Answer
    • 7. m + n + p વસ્તુઓમાંથી m, n અને p વસ્તુઓને ત્રણ ખાનામાં કુલ ........ રીતે મૂકી શકાય ?
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold space bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p bold space bold factorial end fraction bold space bold cross times bold space bold 3
    • fraction numerator bold left parenthesis bold m bold space bold space bold n bold space bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p bold space bold factorial end fraction bold space bold cross times bold space bold 1 over bold 6
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold space bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p bold space bold factorial end fraction
    • fraction numerator bold left parenthesis bold m bold space bold plus bold space bold n bold space bold plus bold space bold p bold right parenthesis bold space bold factorial over denominator bold m bold space bold factorial bold space bold n bold space bold factorial bold space bold p bold space bold factorial end fraction bold space bold cross times bold space bold 3 bold space bold factorial
    Answer
    • 8. 100 વ્યક્તિઓમાંથી 20 ચોક્કસ વ્યક્તિઓ આવે જ તે રીતે 30 વ્યક્તિઓને એક હારમાં કેટલી રીતે ગોઠવી શકાય ?
    • open parentheses table row bold 100 row bold 20 end table close parentheses open parentheses table row bold 80 row bold 10 end table close parentheses bold space bold 30 bold factorial
    • open parentheses table row bold 80 row bold 10 end table close parentheses bold space bold 30 bold factorial
    • 20 × 80 P 10
    • 80 P 10 × 30!
    Answer
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    9. જો bold m bold space bold equals bold space bold sum from bold r bold equals bold 0 to bold 100 of bold space fraction numerator bold 1 over denominator open parentheses table row bold 100 row bold r end table close parentheses end fraction bold comma  તો bold sum from bold r bold equals bold 0 to bold 100 of bold space fraction numerator bold r over denominator open parentheses table row bold 100 row bold r end table close parentheses end fraction bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold space
    • 100 m
    • 200 m
    • 50 m 
    • 99 m
    Answer
    • 10. mn ભિન્ન વસ્તુઓનું n સમાન ભાગમાં ........ રીતે વિભાજન કરી શકાય.
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction bold cross times bold space fraction numerator bold 1 over denominator bold n bold space bold factorial end fraction
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction
    • fraction numerator bold left parenthesis bold m bold space bold n bold right parenthesis bold space bold factorial over denominator bold left parenthesis bold m bold space bold factorial bold right parenthesis to the power of bold n end fraction bold cross times bold 1 over bold n

    • આપેલ પૈકી એક પણ નહી 

    Answer
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