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Gujarati JEE Mathematics : લક્ષ-સાતત્ય અને વિકલન

Multiple Choice Questions

111. f(x) [(1+x)(1+X²)(1+X⁴) ......... n પદ],તો f $open parentheses bold 1 over bold 2 close parentheses$ = ........

112.

જો g : (-∞, ∞) → $open parentheses fraction numerator bold minus bold pi over denominator bold 2 end fraction bold comma bold pi over bold 2 close parentheses$ g(x) 2 tan^-1 (e^x)- $fraction numerator bold minus bold pi over denominator bold 2 end fraction$ અને f એ g નું પ્રતિવિધેય હોય તો f'(0) = ........

Tips: -

અહીં f = g^-1. આથી g^-1(x) = f(x)

અહીં g(x) = y = 2 tan^-1 (e^x)- $bold pi over bold 2$

∴ tan-1 (e^x) = $bold pi over bold 4 bold plus bold space bold y over bold 2$

∴ x = log tan $open parentheses bold pi over bold 4 bold plus bold space bold y over bold 2 close parentheses$

∴ g-1 = log tan $open parentheses bold pi over bold 4 bold plus bold space bold y over bold 2 close parentheses$

∴ g-1 (x) = log tan $open parentheses bold pi over bold 4 bold plus bold space bold x over bold 2 close parentheses$

∴ f(x) = log tan $open parentheses bold pi over bold 4 bold plus bold space bold x over bold 2 close parentheses$

∴ f'(x) = $fraction numerator bold 1 over denominator bold tan open parentheses bold pi over bold 4 bold plus bold space bold x over bold 2 close parentheses end fraction bold space bold sec to the power of bold 2 bold space open parentheses fraction numerator begin display style bold pi end style over denominator begin display style bold 4 end style end fraction bold plus bold space fraction numerator begin display style bold x end style over denominator begin display style bold 2 end style end fraction close parentheses bold space bold times bold space bold 1 over bold 2$

∴ f'(0)= $fraction numerator bold 1 over denominator bold tan bold space begin display style bold pi over bold 4 end style end fraction bold space bold sec to the power of bold 2 bold space fraction numerator begin display style bold pi end style over denominator begin display style bold 4 end style end fraction bold space bold times bold space bold 1 over bold 2 bold space bold equals bold 1$

113.

વિધેય f : R → R માટે નીચે આપેલ પૈકી કયા વિધન સત્ય (T) કે મિથ્યા (F) છે ?

(1) જો |f(x) - f(y)|≤30 |x - y|, ∀x, y, ∈ R, તો f એ R પર સતત વિધેય છે.
(2) જો |f(x) - f(y)|≤30 |x - y|, ∀x, y, ∈ R, તો f એ R પર વિકલનીય વિધેય છે.
(3) જો |f(x) - f(y)|≤21 |x - y|², ∀x, y, ∈ R, તો f એ R પર વિકલનીય વિધેય છે.
(4) જો |f(x) - f(y)|≤21 |x - y|², ∀x, y, ∈ R, તો f એ અચળ વિધેય છે.

TFTF
FTTF
TFTT
TTTT

114.

f એ વિકલનીય વિધેય છે તથા $bold f open parentheses bold x over bold y close parentheses bold space bold equals bold space fraction numerator bold f bold left parenthesis bold x bold right parenthesis over denominator bold f bold left parenthesis bold y bold right parenthesis end fraction bold comma$ x#0, y#0, f(y) # 0 છે. જો f'(1) = 2 હોય તો f'(1) = 2 હોય તો f'(x) = .......

2x f(x)
2 f(x)
$fraction numerator bold 2 bold f bold left parenthesis bold x bold right parenthesis over denominator bold x end fraction$
$fraction numerator bold f bold left parenthesis bold x bold right parenthesis bold space over denominator bold x end fraction$

115. જો f(x) = |x|, g(x) = sin x અને h(x) = g(x) f(g(x)) તો .......

h(x) એ સતત વિધેય તેમજ વિકલનીય વિધેય છે.
h(x) એ સતત વિધેય છે અને ફક્ત x = 0 આગળ વિકલનીય છે.
h(x) એ અસતત વિધેય છે.
h(x) એ સતત વિધેય છે પરંતુ x = 0 આગળ વિકલનીય નથી.

116.

વિધેય f(x) માટે f'(x) + f(x) = 0, ∀ x અને g(x) = [f(x)]² + [f'(x)]² તથા g(3) = 8 તો g(8) = ........

117. $bold જ ો bold space bold y bold space bold equals bold space bold 2 to the power of bold x to the power of bold 2 to the power of bold x end exponent end exponent bold space bold x to the power of bold 2 to the power of bold x end exponent bold space bold ત ો bold space bold dy over bold dx$ = ......

$bold 2 to the power of bold x to the power of bold 2 to the power of bold x end exponent end exponent bold space bold left parenthesis bold 1 bold space bold minus bold space bold x bold space bold log subscript bold e bold 2 bold right parenthesis bold space bold 2 to the power of bold x bold space bold log subscript bold e bold 2$
$bold space bold 2 to the power of bold x to the power of bold 2 to the power of bold x end exponent end exponent bold space bold left parenthesis bold space bold 1 bold space bold plus bold space bold log subscript bold e bold 2 bold right parenthesis bold space bold 2 to the power of bold x bold space bold left parenthesis bold log subscript bold e bold 2 bold right parenthesis to the power of bold 2$
$bold 2 to the power of bold x to the power of bold 2 to the power of bold x end exponent end exponent bold space bold left parenthesis bold 1 bold space bold plus bold space bold x bold space bold log subscript bold e bold 2 bold right parenthesis bold space bold 2 to the power of bold x bold space bold log subscript bold e bold 2$
$bold space bold 2 to the power of bold x to the power of bold 2 to the power of bold x end exponent end exponent bold space bold x to the power of bold 2 to the power of bold x end exponent bold space bold log subscript bold e bold 2 bold space open parentheses bold 2 bold x bold space bold log subscript bold e bold space bold xlog subscript bold e bold space bold 2 bold plus bold space bold 2 to the power of bold x over bold x close parentheses$

118.

bold જ ો bold space bold f bold left parenthesis bold x bold right parenthesis bold space bold equals bold space bold lim with bold n bold rightwards arrow bold infinity below bold space open parentheses bold n-th root of bold x bold minus bold 1 end root close parentheses bold space bold n bold space bold ત ો bold space fraction numerator bold 1 over denominator bold f bold apostrophe bold left parenthesis bold 2012 bold right parenthesis end fraction bold comma bold space fraction numerator bold 1 over denominator bold f bold apostrophe bold left parenthesis bold 2013 bold right parenthesis end fraction bold comma bold space fraction numerator bold 1 over denominator bold f bold apostrophe bold left parenthesis bold 2014 bold right parenthesis end fraction bold space bold એ bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold. bold.

સ્વરિત શ્રેણિમાં હોય.
સમાંતર શ્રેણીમાં હોય.
સમગુણોત્તર શ્રેણીમાં હોય.
એક પણ નહિ.

119.

જો વિધેય g(x) એ વિધેય f(x)નું પ્રતિવિધેય હોય અને f'(x) = $fraction numerator bold 1 over denominator bold 1 bold equals bold x to the power of bold 3 end fraction$ તો g(x) = .......

1+[g(x)]³
1+ g(x)
g(x)
$fraction numerator bold 1 over denominator bold 1 bold plus bold left square bracket bold g bold left parenthesis bold x bold right parenthesis bold right square bracket to the power of bold 3 end fraction$

120.

bold જ ો bold space bold y bold space bold equals bold space square root of bold 2 bold x bold space bold minus bold space bold x to the power of bold 2 end root bold space bold મ ા ટ ે bold comma bold comma bold space bold y to the power of bold 3 bold space fraction numerator bold d to the power of bold 2 bold y over denominator bold dx to the power of bold 2 end fraction bold space bold plus bold space bold k bold space bold equals bold space bold 0 bold comma bold space bold હ ો ય bold space bold ત ો bold space bold k bold space bold equals bold space bold. bold. bold. bold. bold. bold.

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Gujarati JEE Mathematics : લક્ષ-સાતત્ય અને વિકલન

Multiple Choice Questions

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