Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Gujarati JEE Mathematics : શ્રેણિક

Multiple Choice Questions

41.

bold જ ો bold space bold 2 bold space bold X bold space bold plus bold space open square brackets table row bold 1 bold 2 row bold 3 bold 4 end table close square brackets bold space bold equals bold space open square brackets table row bold 3 bold 8 row bold 7 bold 2 end table close square brackets bold space bold ત ો bold space bold X bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold space

$open square brackets table row bold 1 bold 3 row bold 2 cell bold minus bold 1 end cell end table close square brackets$
$open square brackets table row bold 1 cell bold minus bold 3 end cell row bold 2 cell bold minus bold 1 end cell end table close square brackets$
$bold 2 open square brackets table row bold 1 bold 3 row bold 2 cell bold minus bold 1 end cell end table close square brackets$
$bold 2 bold space open square brackets table row bold 1 cell bold minus bold 3 end cell row bold 2 cell bold minus bold 1 end cell end table close square brackets$

42.

bold જ ો bold space bold A bold space bold equals bold space open square brackets table row bold 1 bold 1 row bold 0 bold 1 end table close square brackets bold comma bold space bold B bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold. bold space bold જ ે થ ી bold space bold space bold AB bold space bold equals bold space bold BA bold. bold space bold જ ્ ય ાં bold space bold B bold space bold # bold space bold 1 bold space

$open square brackets table row bold x bold x row bold 1 bold x end table close square brackets$
$open square brackets table row bold x bold y row bold 0 bold y end table close square brackets$
$open square brackets table row bold x bold y row bold 0 bold x end table close square brackets$
$open square brackets table row bold x bold x row bold y bold 0 end table close square brackets$

43. જો A = diag [3 2 1], તો ઍ-1 ના ઘટકોનો સરવાળો ......... છે.

$bold 1 over bold 6$
$bold 5 over bold 6$
$bold 11 over bold 6$
6

44.

bold A bold space bold equals bold space open square brackets table row bold 1 bold 3 row bold 3 bold 4 end table close square brackets bold space bold અન ે bold space bold A to the power of bold 2 bold space bold minus bold space bold 5 bold A bold space bold equals bold space bold kI bold space bold ત ો bold space bold space bold k bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold space

45. જો ચોરસ શ્રેણિક A અને B માટે AB અને BA = B તો B² = ......

46.

bold જ ો bold space bold A bold space bold equals bold space bold left square bracket bold 2 bold space bold minus bold space bold 3 bold space bold 4 bold right square bracket bold comma bold space bold B bold space bold equals bold space open square brackets table row bold 3 row bold 2 row bold 1 end table close square brackets bold comma bold space bold X bold space bold equals bold space bold left square bracket bold 0 bold space bold 2 bold space bold 3 bold right square bracket bold space bold અન ે bold space bold Y bold space bold equals bold space open square brackets table row bold 2 row bold 2 row bold 4 end table close square brackets bold space bold ત ો bold space bold AB bold space bold plus bold space bold XY bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold space

20
-20
[-20]
[20]

47. જો $bold A bold space bold equals bold space open square brackets table row cell bold 3 bold a end cell bold b bold c row bold b cell bold 3 bold c end cell bold a row bold c bold a cell bold 3 bold b end cell end table close square brackets$ ; a,b,c ∈ R, abc = 1, AAT = 64 I અને |A| > તો (a³ + B³ + C³)³

48. જો $bold A bold space bold equals bold space open square brackets table row cell bold minus bold 1 end cell cell bold minus bold 2 end cell cell bold minus bold 2 end cell row bold 2 bold 1 cell bold minus bold 2 end cell row bold 2 cell bold minus bold 2 end cell bold 1 end table close square brackets$ તો adj A = .......

3A^T
3A
A^T
A

49.

bold જ ો bold space bold A bold space bold equals bold space open square brackets table row bold 1 bold cotθ row bold cotθ bold 1 end table close square brackets bold space bold મ ા ટ ે bold space bold left parenthesis bold A to the power of bold minus bold 1 end exponent bold right parenthesis to the power of bold 2 bold space bold F bold left parenthesis bold theta bold right parenthesis bold space open square brackets table row cell bold minus bold cos bold 2 bold theta end cell cell bold minus bold sin bold 2 bold theta end cell row cell bold sin bold 2 bold theta end cell cell bold minus bold cos bold 2 bold theta end cell end table close square brackets bold space bold ત ો bold space bold f bold left parenthesis bold theta bold right parenthesis bold space bold equals bold space bold. bold. bold. bold. bold. bold. bold. bold space

cos²θ
cos θ
sin θ
sin²θ

sin²θ

Tips: -

bold ⌠ bold A bold vertical line bold space bold equals bold space open vertical bar table row bold 1 bold cotθ row bold cotθ bold 1 end table close vertical bar bold space bold equals bold space bold 1 bold space bold plus bold space bold cot to the power of bold 2 bold theta bold space bold equals bold space bold cosec to the power of bold 2 bold theta bold A to the power of bold minus bold 1 end exponent bold space bold equals bold space fraction numerator bold 1 over denominator bold vertical line bold A bold vertical line end fraction bold space bold adj bold space bold A bold space bold A bold minus bold 1 bold space bold equals bold space fraction numerator bold 1 over denominator bold cosec to the power of bold 2 bold theta end fraction bold space open square brackets table row cell table row bold 1 cell bold minus bold cotθ end cell row bold cotθ bold 1 end table end cell end table close square brackets bold left parenthesis bold A to the power of bold minus bold 1 end exponent bold right parenthesis to the power of bold 2 bold space bold equals bold space bold sin to the power of bold 4 bold theta bold space open square brackets table row cell table row bold 1 cell bold minus bold cotθ end cell row bold cotθ bold 1 end table end cell end table close square brackets bold space open square brackets table row cell table row bold 1 cell bold minus bold cotθ end cell row bold cotθ bold 1 end table end cell end table close square brackets bold sin to the power of bold 4 bold theta bold space bold space open square brackets table row cell table row cell bold 1 bold minus bold cot to the power of bold 2 bold theta end cell cell bold minus bold 2 bold cotθ end cell row cell bold 2 bold cotθ end cell cell bold minus bold cot to the power of bold 2 bold theta bold 1 end cell end table end cell end table close square brackets bold equals bold space bold sin to the power of bold 2 bold theta bold space open square brackets table row cell bold sin bold 2 bold theta bold space bold minus bold space bold cos to the power of bold 2 bold theta end cell cell bold minus bold sinθcosθ end cell row cell bold 2 bold sinθcosθ end cell cell bold sin to the power of bold 2 bold theta bold minus bold cos to the power of bold 2 bold theta end cell end table close square brackets bold equals bold space bold sinθ bold space open square brackets table row cell bold minus bold cos bold 2 bold theta end cell cell bold minus bold sin bold 2 bold theta end cell row cell bold sin bold 2 bold theta end cell cell bold minus bold cos bold 2 bold theta end cell end table close square brackets bold therefore bold space bold f bold left parenthesis bold theta bold right parenthesis bold space bold equals bold space bold sin to the power of bold 2 bold theta

50.

જો સમીકરણ λx + 2y - 2z = I, 4x + 2λy - z = 2 અને 6x + 6y + λz = 3, નો અનન્ય ઉકેલ મળે તો,

λ#1
λ#2
λ#3
λ#-2

Switch

Book Store

Subject

Gujarati JEE Mathematics : શ્રેણિક

Multiple Choice Questions

Switch