àªàª• à from Class Chemistry રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

131.

નિયત તાપમાને x મ્હો (સેમી)^-1 વિશિષ્ટ વાહકતા ધરાવતા KCl ના એક જલીય દ્વાવણનો અવરોધ માપતા

bold yΩ

મળે છે, જો તે જ સાધનથી NaCl ના જલીય દ્વાવણનો અવરોધ

bold zΩ

મળે, તો આ દ્વાવણની વિશિષ્ટ વાહકતા કેટલી થાય ?

$xy over 2$ મ્હો (સેમી)^-1
$xy over straight z$ મ્હો (સેમી)^-1
$straight x over yz$ મ્હો (સેમી)^-1
$yz over straight x$ મ્હો (સેમી)^-1

132.

625 Sm²mol^-1
62.5 Sm²mol^-1
6.25 × 10^-2 Sm²mol^-1
6.25 × 10^-4 Sm²mol^-1

D.

6.25 × 10^-4 Sm²mol^-1

0.2 M àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ àª§àª°àª¾àªµàª¤àª¾ àª¦à«àªµàª¾àªµàª£ àª®àª¾àªŸà«‡ R = 50 $straight capital omega$ àª…àª¨à«‡ K = 1.3 S m^-1 = 0.013 S cm^-1

àª•à«‹àª·àªšàª³àª¾àª‚àª• $equals space 1 over straight A space equals space straight K times straight R space equals space 0.013 space cross times space 50 space equals space 0.65 space cm to the power of negative 1 end exponent$

àª¹àªµà«‡ 0.4M àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ àª§àª°àª¾àªµàª¤àª¾ àªœàª²à«€àª¯ àª¦à«àªµàª¾àªµàª£ àª®àª¾àªŸà«‡ R =260 $straight capital omega$ àª†àªªà«‡àª² àª›à«‡.

$straight K space equals space 1 over straight R space space cross times space 1 over straight A space equals space 1 over 260 space cross times space 0.65 space equals space 0.0025 space straight S space cm to the power of negative 1 end exponent$

àª¹àªµà«‡ $increment subscript straight m space equals space fraction numerator 1000 space cross times space straight K over denominator straight C end fraction space space therefore space increment straight m space equals space fraction numerator 1000 space cross times space 0.0025 over denominator 0.4 end fraction space equals space 6.25$

$straight S space space cm squared space mol to the power of negative 1 end exponent space space therefore space increment straight m space equals space 6.25 space cross times space 10 to the power of negative 4 end exponent space straight S space straight m squared space mol to the power of negative 1 end exponent$

0.2 M àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ àª§àª°àª¾àªµàª¤àª¾ àª¦à«àªµàª¾àªµàª£ àª®àª¾àªŸà«‡ R = 50 $straight capital omega$ àª…àª¨à«‡ K = 1.3 S m^-1 = 0.013 S cm^-1

àª•à«‹àª·àªšàª³àª¾àª‚àª• $equals space 1 over straight A space equals space straight K times straight R space equals space 0.013 space cross times space 50 space equals space 0.65 space cm to the power of negative 1 end exponent$

àª¹àªµà«‡ 0.4M àª¸àª¾àª‚àª¦à«àª°àª¤àª¾ àª§àª°àª¾àªµàª¤àª¾ àªœàª²à«€àª¯ àª¦à«àªµàª¾àªµàª£ àª®àª¾àªŸà«‡ R =260 $straight capital omega$ àª†àªªà«‡àª² àª›à«‡.

$straight K space equals space 1 over straight R space space cross times space 1 over straight A space equals space 1 over 260 space cross times space 0.65 space equals space 0.0025 space straight S space cm to the power of negative 1 end exponent$

àª¹àªµà«‡ $increment subscript straight m space equals space fraction numerator 1000 space cross times space straight K over denominator straight C end fraction space space therefore space increment straight m space equals space fraction numerator 1000 space cross times space 0.0025 over denominator 0.4 end fraction space equals space 6.25$

$straight S space space cm squared space mol to the power of negative 1 end exponent space space therefore space increment straight m space equals space 6.25 space cross times space 10 to the power of negative 4 end exponent space straight S space straight m squared space mol to the power of negative 1 end exponent$

133.

$bold N over bold 50 bold KCl$ નું દ્વાવણનું ધરાવતા કોષનો અવરોધ અને વિશિષ્ટ વાહકતા અનુક્રમે 400 Ω અને 0.002765 મ્હો. S $times$ cm^-1 છે, તો તે કોષનો કોષ-અચળાંક કેટલો હશે ?

1.106 cm^-1
1.106 cm^-1
0.172 cm^-1
0.1172 cm^-1

134.

18 $degree$ સે તાપમાને $bold N over bold 10 bold space bold KCl$ નું દ્વાવણ ધરાવતા વાહકતાકોષની વિશિષ્ટવાહકતા 1.12 × 10^-2 S $times$ cm^-1 અને અવરોધ 65 Ω હોય, તો તે કોષનો કોષ-અચળાંક કેટલો થાય ?