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NEET Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions

71. પ્રક્રિયાની પૂર્ણતા પ્રાપ્ત કરવા માટે પ્રક્રિયકના અણુઓ પાસે જરૂરી ઓછામાં ઓછી ઊર્જા એટલે .....

સ્થિતિમાન ઊર્જા
દેહલી ઊર્જા
આંતરિક ઊર્જા
સક્રિયકરણ ઊર્જા

72. નીચેના પૈકી કયું સાચું આર્હેનિયસ સમીકરણ છે ?

$straight K space equals space straight A space times space straight e to the power of begin inline style bevelled fraction numerator negative Ea over denominator RT end fraction end style end exponent$
$In space straight K space equals space In space straight A space minus space Ea over RT$
$In space straight K subscript 2 over straight K subscript 1 space equals space Ea over straight R space open parentheses 1 over straight T subscript 1 space minus space 1 over straight T subscript 2 close parentheses$
આપેલ બધા જ

73.

20 àª®àª¿àª¨àª¿àªŸ
40 àª®àª¿àª¨àª¿àªŸ
10 àª®àª¿àª¨àª¿àªŸ
80 àª®àª¿àª¨àª¿àªŸ

74.

15 àª®àª¿àª¨àª¿àªŸ
45 àª®àª¿àª¨àª¿àªŸ
60 àª®àª¿àª¨àª¿àªŸ
30 àª®àª¿àª¨àª¿àªŸ

60 àª®àª¿àª¨àª¿àªŸ

$straight K space equals space fraction numerator 2.303 over denominator straight t end fraction space log space straight N subscript 0 over straight N subscript straight t space equals space fraction numerator 2.303 over denominator 2 space cross times space 60 end fraction space log space fraction numerator 1 over denominator 1 minus begin display style 3 over 4 end style end fraction space equals space fraction numerator 2.303 over denominator 120 end fraction log space 4 space equals space 0.01155 space àª® àª¿ àª¨ àª¿ àªŸ à«‡ to the power of negative 1 end exponent straight t subscript begin inline style bevelled 1 half end style end subscript space equals space fraction numerator 0.693 over denominator straight K end fraction space equals space fraction numerator 0.693 over denominator 0.01155 end fraction space equals space 60 space àª® àª¿ àª¨ àª¿ àªŸ$

75.

46.06 àª®àª¿àª¨àª¿àªŸ
460.6 àª®àª¿àª¨àª¿àªŸ
23.03 àª®àª¿àª¨àª¿àªŸ
230.5 àª®àª¿àª¨àª¿àªŸ

76.

$fraction numerator 0.346 over denominator straight K end fraction$
$fraction numerator 0.25 over denominator straight K end fraction$
$fraction numerator 0.29 over denominator straight K end fraction$
$fraction numerator 1.38 over denominator straight K end fraction$

77.

$bold N subscript bold 2 bold O subscript bold 5 bold space bold rightwards arrow bold space bold 2 bold NO subscript bold 2 bold space bold plus bold space bold 1 over bold 2 bold O subscript bold 2 bold space$ àªªà«àª°àª•à«àª°àª¿àª¯àª¾àª¨à«‹ $bold t subscript begin inline style bold 1 over bold 2 end style end subscript bold space bold equals bold space bold 24$ àª•àª²àª¾àª• àª›à«‡. 10 àª—à«àª°àª¾àª® N₂O₅ àª¨à«àª‚ àªµàª¿àª˜àªŸàª¨ àª•àª°àªµàª¾àª¥à«€ 96 àª•àª²àª¾àª• àªªàª›à«€ àª¬àª¾àª•à«€ àª°àª¹à«‡àª¤à«‹ N₂O₅ àª¨à«‹ àªœàª¥à«àª¥à«‹ àª•à«‡àªŸàª²à«‹ àª¹àª¶à«‡ ?

1.25 àª—à«àª°àª¾àª®
1.77 àª—à«àª°àª¾àª®
0.63 àª—à«àª°àª¾àª®
0.5 àª—à«àª°àª¾àª®

78.

360 àª®àª¿àª¨àª¿àªŸ
300 àª®àª¿àª¨àª¿àªŸ
398.8 àª®àª¿àª¨àª¿àªŸ
400 àª®àª¿àª¨àª¿àªŸ

79. પ્રથમ ક્રમની એક પ્રક્રિયામાં 75 % પ્રક્રિયકનું વિઘટન 1.386 કલાકમાં થાય છે. આ પ્રક્રિયાનો વેગ-અચળાંક જણાવો.

$1.8 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$2.8 space cross times space 10 to the power of negative 4 end exponent space straight s to the power of negative 1 end exponent$
$17.2 space cross times 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$
$3.6 space cross times space 10 to the power of negative 3 end exponent space straight s to the power of negative 1 end exponent$

80.

$3.466 space cross times 10 to the power of negative 3 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 4 end exponent straight M$ àª®àª¿àª¨àª¿àªŸ^-1
$3.466 space cross times space 10 to the power of negative 5 end exponent space straight M$ àª®àª¿àª¨àª¿àªŸ^-1
àª†àªªà«‡àª² àªªà«ˆàª•à«€ àªàª• àªªàª£ àª¨àª¹à«€

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NEET Chemistry : રસાયણિક ગતિકી

Multiple Choice Questions