Important Questions of રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ for NEET Chemistry | Zigya

Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Subject

Chemistry
Advertisement
zigya logo

NEET Chemistry : રેડોક્ષ પ્રક્રિયા અને વિદ્યુતરસાયણ

Multiple Choice Questions

141. આપેલમાંથી કોની અનંતમંદને તુલ્યવાહકતા સૌથી વધારે છે ?
  • Rb(aq)

  • Cs(aq)

  • Na(aq)

  • K(aq)


142. આપેલ કયા સંયોજન માટે મોલરવાહકતા અને (મોલારિટી)1/2 નો આલેખ સીધી રેખા મળે છે ?
  • CsCl

  • NH4OH

  • HCOOH

  • આપેલ ત્રણેય માટે 

143. bold 1 over bold 3 bold capital lambda to the power of bold 0 subscript bold mAl to the power of bold 3 end subscript bold space bold equals bold space bold 63 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold 1 over bold 2 bold capital lambda to the power of bold 0 subscript bold mMg to the power of bold 2 end subscript bold space bold equals bold space bold 53 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 subscript bold mOH to the power of bold minus end subscript bold space bold equals bold 199 bold. bold 1 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold 1 over bold 2 bold capital lambda to the power of bold 0 bold SO presubscript bold m subscript bold 4 to the power of bold 3 bold minus end exponent bold space bold equals bold space bold 80 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponentસમૂહ-1 માં આપેલ સંયોજન અને સમૂહ-2 આપેલ અનંતમંદને મોલરવાહકતા માટે યોગ્ય વિકલ્પ પસંદ કરો.


  • (i)-(F), (ii)-(D), (iii)-(H), (iv)-(B)

  • (i)-(C), (ii)-(D), (iii)-(H), (iv)-(B)

  • (i)-(F), (ii)-(A), (iii)-(E), (iv)-(G)

  • (i)-(C), (ii)-(G), (iii)-(A), (iv)-(E)


144. bold capital lambda subscript bold m bold space bold equals bold space bold capital lambda to the power of bold 0 subscript bold m bold space bold minus bold space bold A bold times bold C to the power of begin inline style bold 1 over bold 2 end style end exponentકયા સયોજનને લાગુ પડે છે ?
  • NH4OH

  • HCOOH

  • NaCl

  • HCN


Advertisement
145. આપેલમાંથી  કયો પદાર્થ અર્ધવાહક છે ?
  • કાચ

  • CuO

  • Cu2O

  • ટેફલોન


146. આપેલમાંથી કયા વિકલ્પના બધા જ વિદ્યુતવિભાજ્યોના જલીય દ્વાવણ માટે bold capital lambda subscript bold m bold space bold rightwards arrow square root of bold C ના આલેખનો ઢાળ સમાન હોય છે.
(i) NaCl (ii) NH4OH (iii) KNO3 (v) KBr (Vi) HCN (vii) CaCl2 (viii) FeCl3
  • (i), (v), (vi)

  • (iii), (viii)

  • (i), (iii), (v)

  • (ii), (iv), (viii)


147. એક પ્રબળ વિદ્યુતવિભાજ્ય માટે C = 0.04 M હોય, ત્યારે bold capital lambda subscript bold m bold space bold equals bold space bold 250 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent છે C = 0.09 M અને હોય ત્યારે bold capital lambda subscript bold m bold space bold equals bold space bold 200 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent છે તો તે વિદ્યુતવિભાજ્ય માટે straight capital lambda spaceઅને bold capital lambda subscript bold m superscript bold 0 અનુક્રમે કેટલા હશે ?
  • 550, 265 S cm2mol-1

  • 500, 350 S cm2mol-1

  • 340, 450 S cm2mol-1

  • 450, 365 S cm2mol-1


148.
bold capital lambda to the power of bold 0 subscript bold mMg to the power of bold 2 end subscript bold equals bold space bold 106 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 subscript bold mCa to the power of bold 2 to the power of blank end exponent end subscript bold space bold equals bold space bold 119 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold 0 bold space bold comma bold space bold capital lambda to the power of bold 0 subscript bold mCl to the power of bold minus end subscript bold space bold equals bold space bold 76 bold. bold 3 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold spacebold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold comma bold space bold capital lambda to the power of bold 0 bold SO presubscript bold m subscript bold 4 to the power of bold 2 bold minus end exponent bold space bold equals bold space bold 160 bold space bold S bold space bold cm to the power of bold 2 bold mol to the power of bold minus bold 1 end exponent bold spaceસમૂહ-1 માં આપેલ સંયોજક અને સમૂહ-2 માં આપેલ અનંતમંદને મોલરવાહકતા માટે યોગ્ય વિકલ્પ પસંદ કરો. 

  • (i)-(F), (ii)-(D), (iii)-(H), (iv)-(B)

  • (i)-(C), (ii)-(D), (iii)-(H), (iv)-(B)

  • (i)-(F), (ii)-(A), (iii)-(E), (iv)-(G)

  • (i)-(C), (ii)-(G), (iii)-(A), (iv)-(E)


Advertisement
Advertisement