Multiple Choice Questions

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The lattice enthalpy and hydration enthalpy of four compounds are given below

Compound Lattice enthalpy (in kJ mol-1) Hydration
enthalpy
(in kJ mol-1)
P +780 -920
Q +1012 -812
R +828 -878
S +632 -600

The pair of compound which is soluble in water is

  • P and R

  • Q and R

  • P and Q

  • Rand S


A.

P and R

The solubility of a compound mainly depends upon its hydration energy. If the hydration energy of a compound is greater than from its lattice enthalpy, then it is soluble in water. Thus, for solubility hydration enthalpy > lattice enthalpy For compounds P and R hydration enthalpy exceeds the lattice enthalpy, so they are soluble in water.


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In which one of the following pairs the radius of the second species is greater than that of the first?

  • Na, Mg

  • O2-, N3-

  • Li+, Be2+

  • Ba2+, Sr2+


The first ionisation energy of oxygen is less than that of nitrogen. Which of the following is the correct reason for this observation?

  • Lesser effective nuclear charge of oxygen than nitrogen.

  • Lesser atomic size of oxygen than nitrogen

  • Greater interelectron repulsion between two electrons in the same p-orbital counter balances the increase in effective nuclear charge on moving from nitrogen to oxygen.

  • Greater effective nuclear charge of oxygen than nitrogen.


The first () and second (ΔH2) ionisation enthalpies (in kJ mol-1) and the (ΔegH) electron gain enthalpy (in kJ mol-1) of the elements I, II, III, IV and V are given below

Element ΔH1 ΔH2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 2372 5251 +48

The most reactive metal and the least reactive non-metal of these are respectively

 

  • I and IV

  • IV and II

  • II and IV

  • III and IV


'Hydride Gap' is referred to which region of the Periodic Table ?

  • Groups 3, 4 and 5

  • Groups 5, 6 and 7

  • Groups 4, 5 and 6

  • Groups 7, 8 and 9


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In which of the following the oxidation number of oxygen has been arranged in increasing order?

  • OF2 < KO2 < BaO2 < O3

  • BaO2 < KO2  < O< OF2 

  • BaO2  < O< OF2  < KO2 

  •  KO2  < OF2  < O< BaO2 


The correct decreasing order of first ionisation enthalpies of five elements of the second period is

  • Be > B > C > N > F

  • N > F > C > B > Be

  • F > N > C > Be > B

  • N > F > B > C > Be


The correct match of contents in Column I with those in Column II is

  Column I   Column II
(A) He (i) High electron affinity
(B) Cl (ii) Most electropositive element
(C) Ca (iii) Strongest reducing agent
(D) Li (iv) Highest ionisation energy
  • A-iv, B-i, C-ii, D-iii

  • A-iii, B-i, C-ii, D-iv

  • A-iv, B-iii, C-ii, D-i

  • A-ii, B-iv, C-i, D-iii


The electronic configuration of the element with maximum electron affinity is

  • 1s2, 2s2,2p3

  • 1s2, 2s2,2p5

  • 1s2, 2s2,2p6, 3s2, 3p5

  • 1s2, 2s2,2p6, 3s2, 3p3


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The one electron species having ionization energy of 54.4 eV is :

  • H

  • He+

  • B4+

  • Li2+


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