Long Answer Type

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Briefly write the rules for writing the formulas of mononuclear coordination compounds.


Mononuclear coordination compounds are the complex ions which have only one central metal atom or ion.

The formula of such complex compounds are written as per of the following rules:

(i) Central atoms is written first.

(ii) It is followed by the symbols of the ligands which are written in the order-negative ligands, neutral ligands followed by positive ligands.

(iii) If more than one type of ligands are there then their formulae are written according to the alphabetical order of the first symbol of their formulae.

(iv) The number of ligands linked to metal atom are indicated by putting its number as subscript written after simple brackets in which the lingands are placed.

(v) The coordination sphere is enclosed in square brackets.

(vi) No space is kept between representations of ions in the formula, whether the coordination sphere is a cation or anion.

(vii) If the formula of coordination sphere is written without the counter ion then the charge on the coordination sphere is written as a superscript on the right hand side, outside the square brackets, e.g., [Co(NH3)6]Cl3, [Cr(H2O)6]3+ etc.

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Short Answer Type

What is a coordination polyhedron?
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What do you mean be denticity and chelation?
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Long Answer Type

Briefly explain the rules for writing down the names of the coordination compounds.

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Short Answer Type

Briefly classify the type of ligands on the basis of their ligating ability.
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What are ligands? Give examples.

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What do you mean by coordination number? Explain with example.
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What are ambident ligands? What are their importance?

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Long Answer Type

Briefly explain the type of chelation.
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Short Answer Type

On the basis of the following observations made with aqueous solutions, assign primary and secondary valencies to metals in the following compounds:

Formula

Motes of AgCl precipitated with excess AgNO3

(i) PdCl2.4NH3

2

(ii) NiCl2.6H2O

2

(iii) PtCl4.2HCl

0

(iv) CoCl3.4NH3

1

(v) PtCl2.2NH3

0

.

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