Short Answer Type

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Out of the two - trans-but-2-ene and cis-but-1-ene, which is more stable and why


Trans-but-2-ene has less heat of hydrogenation than the cis-isomer, therefore it is more stable. 



In the trans isomer, the two methyl groups are present on the opposite side as compared to cis-isomer. As a result, the Vander Waal's forces of attraction in trans isomer are less. This means that the trans isomer has less heat of hydrogenation and is more stable than the cis-isomer.

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Long Answer Type

How will you explain that there exists two varieties of 1, 2,-dichloroethene while there is only one type of 1, 2-dichloroethane?

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Short Answer Type

What happens when 2-Bromobutane is heated with alcoholic KOH. Account for the product formed.

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Draw cis and trans isomers of the following compounds. Also, write their IUPAC names:

(i) CHCl = CHCl

(ii) C2H5CCH3 = CCH3C2H5 

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Alkanes and alkynes do not exhibit geometrical isomerism. Explain. 

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Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

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Which of the following compounds would show geometrical isomerism? Draw the isomeric structures to support your answer:
(i) But-2-ene
(ii) Pent-1-ene
(iii) 2-Methyl-But -2-ene
(iv) 3, 4-Dimethyl-hex-3-ene

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What happens when butan-2-ol is heated with concentrated H2SO4. Account for the product formed.

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What is Saytzeff’s rule? Explain it with an example. 

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Which of the following compounds will show cis-trans isomerism?

(i)(CH3)2C = CH-C2H5
(ii) CH2 = CBr2
(iii) C2H5CH = CH-CH2
(iv) CH3CH = CClCH3 

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