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Why are Cr2+ reducing and Mn3+ oxidising when both have d4 configurations?


Cr2+ is strongly reducing in nature. It has a d4 configuration. While acting as a reducing agent, it gets oxidized to Cr3+ (electronic configuration, d3). This d3 configuration can be written as 3t2g configuration, which is a more stable configuration.

 
In the case of Mn3+ (d4), it acts as an oxidizing agent and gets reduced to Mn2+ (d5). This has an exactly half-filled d-orbital and has an extra-stability.

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Which element shows the highest oxidation state among the d-block elements?

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What is the reason of transition elements to exhibit variable oxidation states?
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Out of V and Mn which exhibits more oxidation states?
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What is the most stable oxidation state of Mn (Z = 25)?

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Write the highest oxidation state shown by element with atomic number 23.
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The electronic configuration of an element is 3d5 4s1. Write its (i) most stable oxidation state and (ii) most oxidising state.

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The electronic configuration of an element is 3d5 4s1. Write its (i) most stable oxidation states and (ii) most oxidising oxidation state.
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What is the highest oxidation state shown by Cr (Z = 24)?
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The E° value of Zn2+/Zn and Mn2+/Mn are quite low. Why?
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