Multiple Choice Questions

Advertisement

It is because of inability of ns2 electrons of the valence shell to participate in bonding that

  • Sn2+ is reducing while Pb4+ is oxidising

  • Sn2+ is oxidising while Pb4+ is reducing

  • Sn2+ and Pb2+ are both oxidising and reducing

  • Sn2+ and Pb2+ are both oxidising and reducing


A.

Sn2+ is reducing while Pb4+ is oxidising

Inability of ns2 electrons of the valence shell to participate in bonding on moving down the group in heavier p-block elements is called inert pair effect
As a result, Pb(II) is more stable than Pb(IV)
Sn(IV) is more stable than Sn(II)
∴ Pb(IV) is easily reduced to Pb(II)
∴ Pb(IV) is oxidising agent
Sn(II) is easily oxidised to Sn(IV)
∴ Sn(II) is reducing agent

1672 Views

Advertisement

Which one of the following ions is the most stable in aqueous solution?

  • Cr3+

  • V3+

  • Ti3+

  • Ti3+


The shape of gaseous SnCl2 is

  • Tetrahedral

  • Linear

  • Angular

  • T-shape


[CuCl4]2- exists while [CuI4]2- does not exist, because

  • I- is stronger reductant than Cl-

  • I- is weaker reductant than Cl-

  • I- is stronger oxidant than Cl-

  • None of the above


More the number of oxidation states are exhibited by the actinoids than by the lanthanoids. The main reason for this is:

  • more energy difference between 5f and 6d orbitals than that between 4f and 5d orbitals

  • the lesser energy difference between 5f and 6d orbitals than that between 4f and 5d orbitals

  • the greater metallic character of the lanthanoids than that of the corresponding actinoids

  • the greater metallic character of the lanthanoids than that of the corresponding actinoids

503 Views

Advertisement

Actinides exhibit larger number of oxidation state than that of corresponding lanthanides. The reason behind this aspect is

  • lesser energy difference between 5f and 6d-orbitals than between 4f and 5d-orbitals

  • larger atomic size of actinides than the lanthanides

  • more energy difference between 5f and 6d orbitals than between 4f and 5d-orbitals

  • greater reactive nature of the actinides than the lanthanides


Name the gas that can readily decolourises acidified KMnO4 solution

  • CO2

  • SO2

  • NO2

  • NO2

1440 Views

Identify the incorrect statement among the following:

  • There is a decrease in the radii of the atoms or ions as one proceeds from La to Lu.

  • Lanthanoid contraction is the accumulation of successive shrinkages

  • As a result of lanthanoid contraction, the properties of 4d series of the transition elements have no similarities with the 5d series of elements

  • As a result of lanthanoid contraction, the properties of 4d series of the transition elements have no similarities with the 5d series of elements


The reason for greater range of oxidation states in actinoids is attributed to

  • The radioactive nature of actinoids

  • Actinoid contraction

  • 5f, 6d and 7s levels having comparable energies

  • 5f, 6d and 7s levels having comparable energies

1045 Views

Advertisement
<

The correct increasing order of ionic radii of the following Ce3+, La3+, Pm3+ and Yb3+ is 

  • Yb3+ < Pm3+< Ce3+<La3+

  • Ce3+< Yb3+<Pm3+<La3+

  • Yb3+< Pm3+< La3+<Ce3+

  • Pm3+ < La3+< Ce3+ < Yb3+


Advertisement