Multiple Choice Questions

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Which one of the following oxides is amphoteric ?

  • ZnO

  • MgO

  • CaO

  • CO2


A.

ZnO

An amphoteric compound or metal oxide or hydroxide is able to react both as base and as an acid. Therefore, among the given options, ZnO is an amphoteric molecule.


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In which one of the following pairs the radius of the second species is greater than that of the first?

  • Na, Mg

  • O2-, N3-

  • Li+, Be2+

  • Ba2+, Sr2+


'Hydride Gap' is referred to which region of the Periodic Table ?

  • Groups 3, 4 and 5

  • Groups 5, 6 and 7

  • Groups 4, 5 and 6

  • Groups 7, 8 and 9


In which of the following the oxidation number of oxygen has been arranged in increasing order?

  • OF2 < KO2 < BaO2 < O3

  • BaO2 < KO2  < O< OF2 

  • BaO2  < O< OF2  < KO2 

  •  KO2  < OF2  < O< BaO2 


The electronic configuration of the element with maximum electron affinity is

  • 1s2, 2s2,2p3

  • 1s2, 2s2,2p5

  • 1s2, 2s2,2p6, 3s2, 3p5

  • 1s2, 2s2,2p6, 3s2, 3p3


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The one electron species having ionization energy of 54.4 eV is :

  • H

  • He+

  • B4+

  • Li2+


The lattice enthalpy and hydration enthalpy of four compounds are given below

Compound Lattice enthalpy (in kJ mol-1) Hydration
enthalpy
(in kJ mol-1)
P +780 -920
Q +1012 -812
R +828 -878
S +632 -600

The pair of compound which is soluble in water is

  • P and R

  • Q and R

  • P and Q

  • Rand S


The correct match of contents in Column I with those in Column II is

  Column I   Column II
(A) He (i) High electron affinity
(B) Cl (ii) Most electropositive element
(C) Ca (iii) Strongest reducing agent
(D) Li (iv) Highest ionisation energy
  • A-iv, B-i, C-ii, D-iii

  • A-iii, B-i, C-ii, D-iv

  • A-iv, B-iii, C-ii, D-i

  • A-ii, B-iv, C-i, D-iii


Consider the ions : K+, S2-, Cl- and Ca2+. The radii of these ionic species follow the order

  • Ca2+ > K+ > Cl- > S2-

  • Cl- > S2- > K+ > Ca2+

  • S2- > Cl- > K+ > Ca2+

  • Ca2+ > S2- > Cl- > Ca2+


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The first ionisation energy of oxygen is less than that of nitrogen. Which of the following is the correct reason for this observation?

  • Lesser effective nuclear charge of oxygen than nitrogen.

  • Lesser atomic size of oxygen than nitrogen

  • Greater interelectron repulsion between two electrons in the same p-orbital counter balances the increase in effective nuclear charge on moving from nitrogen to oxygen.

  • Greater effective nuclear charge of oxygen than nitrogen.


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