Short Answer TypeGive one chemical test to distinguish between the following pairs of compounds.
Aniline and N — methlyaniline.
Account for the following:
Methylamine in water reacts with ferric chloride to precipitate ferric hydroxide.
a Friedel -crafts reaction is carried out in the presence of AlCl3. but AlCl3 is acidic in nature, while aniline is a strong base. Thus, aniline reacts with AlCl3 to form a salt. Due to the positive charge on the N-atom, electrophilic substitution in the benzene ring is deactivated.Hence, aniline does not under go the Friedel-crafts reactions.
Aniline does not under Friedel-Craft reaction (alkylation and acetylation) due to the salt formation with aluminium chloride, the Lewis acid which is used as a catalyst. Due to this, the nitrogen of aniline acquires a positive charge and hence acts as a strong deactivating group for further reaction.Arrange the following:
In decreasing order of the pKb values C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2.
Arrange the following:
In decreasing order of basic strength:
C6H5NH2, C6HsN(CH3)2, (C2H5)2NH and CH3NH2
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