Which of the following compounds will be suitable for Kjeldah1’s method for nitrogen estimation?
The increasing order of basicity of the following compounds is:
(d) < (b) < (a) < (c)
(a) < (b) < (c) < (d)
(b) < (a) < (c) < (d)
(b) < (a) < (d) < (c)
D.
(b) < (a) < (d) < (c)
Order of base nature depends on electron donation tendency.
It compounds (b) nitrogen is sp2 hybridized so least basic among all given compound
Compound (c) is a very strong nitrogeneous organic base as a lone pair of one nitrogen delocalize in resonance and make another nitrogen negatively charged and conjugate acid have two equivalent resonating structure.
Thus it is most basic in given compound.
(d) is secondary amin more than (a) which is a primary amine.
The compound that does not produce nitrogen gas by the thermal decomposition is
(NH4)2SO4
Ba(N3)2
(NH4)2Cr2O7
NH4NO2
Amongst the following compounds, the one(s) which readily react with ethanolic KCN.
Ethyl chloride
Chlorobenzene
Benzaldehyde
Salicylic acid
An amine C3H9N reacts with benzene sulphonyl chloride to form a white precipitate which is insoluble in aq. NaOH. The amine is
The reaction of aniline with chloroform under alkaline conditions leads to the formation of
phenylcyanide
phenylisonitrile
phenylcyanate
phenylisocyanate
When aniline is nitrated with nitrating mixture in ice cold condition, the major product obtained is
p-nitroaniline
2,4-dinitroaniline
o-nitroaniline
m-nitroaniline
The basicity of aniline is weaker in comparison to that of methyl amine due to
hyperconjugative effect of Me-group in MeNH2
resonance effect of phenyl group in aniline
lower molecular weight of methyl amine as compared to that of aniline
resonance effect of - NH2 group in MeNH2