p-toluidine and benzyl amine can be distinguished by from Chemis

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 Multiple Choice QuestionsMultiple Choice Questions

461.

Which of the following compound is the most basic?


462.

The product formed when phthalimide is treated with a mixture of Br2 and strong NaOH solution is

  • aniline

  • phthalamide

  • phthalic acid

  • anthranilic acid


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463.

p-toluidine and benzyl amine can be distinguished by

  • Sandmeyer's reaction

  • Dye test

  • Molisch test

  • Gattermann reaction


B.

Dye test

p-toluidine contains amino group attached directly to benzene ring, thus undergo diazotisation reaction and gives red dye. In benzyl amine, the amino group is not directly attached to benzene ring. Hence, it will not undergo diazotisation reaction.

                                            ,   

Thus, these two can be distinguished by dye test.


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464.

Which one of the following will be most basic?

  • Aniline

  • p-methoxyaniline

  • p-methyl aniline

  • Benzylamine


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465.

Nitrobenzene can be converted into azobenzene by reduction with

  • Zn, NH4Cl, 

  • Zn/NaOH, CH3OH

  • Zn/NaOH

  • LiAlH4, ether


466.

The one which is least basic is

  • NH3

  • C6H5NH2

  • (C6H5)3N

  • (C6H5)2NH


467.

Which of the following converts CH3CONH2 to CH3NH2?

  • NaBr

  • NaOBr

  • Br2

  • None of the above


468.

The reaction, ROH + H2CN2 in the presence of HBF4, gives the following product

  • ROCH3

  • RCH2OH

  • ROHCN2N2

  • RCH2CH3


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469.

In Gattermann reaction, a diazonium group is replaced by X using Y.X and Y are

  • X Y
    Cl Cu/HCl
  • X Y
    Cl CuCl2/HCl
  • X Y
    Cl CuCl2/HCl
  • X Y
    Cl2 Cu2O/HCl

470.

How many tripeptides can be prepared by linking the amino acids glycine, alanine and phenyl alanine?

  • One

  • Three

  • Six

  • Twelve


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