The product formed when phthalimide is treated with a mixture of Br2 and strong NaOH solution is
aniline
phthalamide
phthalic acid
anthranilic acid
p-toluidine and benzyl amine can be distinguished by
Sandmeyer's reaction
Dye test
Molisch test
Gattermann reaction
B.
Dye test
p-toluidine contains amino group attached directly to benzene ring, thus undergo diazotisation reaction and gives red dye. In benzyl amine, the amino group is not directly attached to benzene ring. Hence, it will not undergo diazotisation reaction.
,
Thus, these two can be distinguished by dye test.
Which one of the following will be most basic?
Aniline
p-methoxyaniline
p-methyl aniline
Benzylamine
Nitrobenzene can be converted into azobenzene by reduction with
Zn/NaOH, CH3OH
Zn/NaOH
LiAlH4, ether
The reaction, ROH + H2CN2 in the presence of HBF4, gives the following product
ROCH3
RCH2OH
ROHCN2N2
RCH2CH3
In Gattermann reaction, a diazonium group is replaced by X using Y.X and Y are
X | Y |
Cu/HCl |
X | Y |
CuCl2/HCl |
X | Y |
CuCl2/HCl |
X | Y |
Cl2 | Cu2O/HCl |
How many tripeptides can be prepared by linking the amino acids glycine, alanine and phenyl alanine?
One
Three
Six
Twelve