Which will not go for diazotisation? from Chemistry Amines

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

471.

Consider the following reaction,

C2H5HCl + AgCN EtOH/H2O X (major)

Which one of the following statements is true for X ?

(I) It gives propionic acid on hydrolysis
(II) It has an ester functional group
(III) It has a nitrogen linked to ethyl carbon
(IV) It has a cyanide group

  • IV

  • III

  • II

  • I


472.

When acetamide is hydrolysed by boiling with acid, the product obtained is

  • acetic acid

  • ethyl amine

  • ethanol

  • acetamide


Advertisement

473.

Which will not go for diazotisation?

  • C6H5NH2

  • C6H5CH2NH2


B.

C6H5CH2NH2

Only 1° aromatic amine (primary aromatic amine) form diazonium salts at low temperature (0°- 5C). A reaction in which -NH2 group is converted into diazo group  () is called diazotisation. Diazotised salts are stable in cold aqueous solution.

aromatic primary amines, so undergo diazotisation but C6H5CH2NH2 (aliphatic amine) will not undergo diazotisation.


Advertisement
474.

Urea on slow heating gives :

  • NH2CONHNO2

  • NH2CONHCONH2

  • HCNO

  • NH2CONH2.HNO3


Advertisement
475.

The correct sequence of base strengths in aqueous solution is :

  • (CH3)2NH > CH3NH2 > (CH3)3N

  • (CH3)3N > CH3NH>(CH3)2NH

  • (CH3)3N > CH3NH2 = (CH3)2NH

  • (CH3)2NH > (CH3)3N > CH3NH2 


476.

When aqueous solution of benzene diazoniumchloride is boiled, the product formed is:

  • C6H5CH2OH

  • C6H+ N2

  • C6H5COOH

  • C6H5OH


477.

Carbylamine reaction is given by aliphatic :

  • primary amine

  • secondary amine

  • tertiary amine

  • quaternary ammonium salt


478.

C6H5CHO  NH3 ?

  • (C6H5CHN)2CH·C6H5

  • C6H5NHCH3

  • C6H5NHCH2

  • C6H5NHC6H5


Advertisement
479.

An organic compound 'A' having molecular formula C2H3N on reduction gave another compound B, upon treatment with nitrous acid 'B' gave ethyl alcohol. On warming with chloroform and alcoholic KOH, it formed an offensive smelling compound 'C'. The compound 'C' is

  • CH3CH2NH2

  • CH3CH2N= C

  • CH3CN

  • CH3CH2.OH


480.

Compound (A) (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2 · HCl and sodium acetate gives a product C'. Identify the structure of 'C

  • CH3CH2CH =NNHCONH2

  • (CH3)2C = NNHCONH2

  • (CH3)2C =NCONHNH2

  • CH3CH2CH= NCONHNH2


Advertisement