0ne mole of hydrazine (N2H4) loses 10 moles of electrons in a reaction to form a new compound X. Assuming that all the nitrogen atoms in hydrazine appear in the new compound, what is the oxidation state of nitrogen in X? (Note - There is no change in the oxidation state of hydrogen in the reaction).
-1
-3
+3
+5
Which one of the following is used as a test for aliphatic primary amines?
Tollen's test
Fehling's test
lsocyanide test
Azo dye test
When methanamine is treated with benzoyl chloride, the major product is
N-phenylethanamide
N-methylbenzamide
benzanilide
acetophenone
Phenyl isocyanide is prepared from aniline by
Carbylamine reaction
Rosenmund's reaction
Koble's reaction
Reimer-Tiemann reaction
Gabriel's phthalimide synthesis can be used to prepare
ethanamine
N-methylmethanamine
benzene amine
N, N-dimethylmethanamine
Select the compound which on treatment with nitrous acid liberates nitrogen.
Nitroethane
Triethylamine
Diethylamine
Ethylamine
The compound that neither forms semicarbazone nor oxime is
HCHO
CH3COCH3
CH3CHO
CH3CH2CH2NH2
D.
CH3CH2CH2NH2
Amine such as CH3CH2CH2NH2 neither form semicarbazide nor oxime.
Positive carbylamine test is shown by
N, N-dimethylaniline
triethylamine
N-methylaniline
p-methylbenzylamine
Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO3/dil.HCl gives compound C. The compounds A, B and C respectively are
ethanamide, methanamine, methanol
propanamide, ethanamine, ethanol
N-ethylpropanamide, methaneisonitrile, methanamine
ethanamine, bromoethane, ethanediazoniumchloride
n-butylamine (l), diethylamine (II) and N, N-dimethylethylamine (III) have the same molar mass. The increasing order of their boiling point is
III < II < I
I < II < III
II < III < I
II < I < III