Correct basicity of the following compounds areI. AnilineII. Pyri

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 Multiple Choice QuestionsMultiple Choice Questions

561.

Mark the correct statement.

  • Methylamine is slightly acidic

  • Methylamine is less basic than NH3

  • Methylamine is stronger base than NH3

  • Methylamine forms salt with alkalies


562.

Which among the following represents an amide?


563.

In the carbylamine reaction, R-X is converted to R-Y via the intermediate Z. R-X, R-Y and Z, respectively, are

  • RNH2, RNC, Carbene

  • RNH2, RNC, nitrene

  • RNC, RNH2, carbene

  • ROH, RNC, nitrene


564.

Which one of the following is the strongest base ?

  • 2,4,6-trinitroaniline

  • 2,4,6-trinitro-N,N-dimethyl aniline

  • N, N-dimethyl aniline

  • Anline


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565.

Hinsberg's reagent is

  • benzene sulphonyl chloride

  • benzene sulphonic acid

  • phenyl isocyanide

  • benzene sulphonamide


566.

The given reaction is called as

  • Schmidt rearrangement

  • Curtius rearrangement

  • Hofmann rearrangement

  • Lossen rearrangement


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567.

Correct basicity of the following compounds are

I. Aniline

II. Pyridine

III. Pyrrole

IV. Guanidine

  • I >II >III >IV

  • III >I >II >IV

  • IV >II >I >III

  • II >IV>III >I


C.

IV >II >I >III

From the structures of the four compounds, It is clear that in pyrrole, the electron pair on nitrogen is involved in delocalisation of the ring. So, it is least basic.
In aniline, the electron pair involved in conjugation with the Π- electrons of the ring while in pyridine it is relatively free. Guandine is a strong base.


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568.

One amine is more basic than ammonia and the other is less basic than ammonia. The two amines are respectively

  • N-methyl ethanamine and N, N-dimethyl ethanamine

  • aniline and N-methyl aniline

  • N-methyl aniline and aniline

  • N, N-dimethyl aniline and benzenamine


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569.

One of the isomer of C4H11N is optically active. It must be a

  • primary amine

  • secondary amine

  • tertiary amine

  • all isomers are optically inactive


570.

Which of the following compounds cannot be identified by carbylamine test?

  • CHCl3

  • C6H5-NH-C6H5

  • C6H5NH2

  • CH3CH2NH2


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