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 Multiple Choice QuestionsMultiple Choice Questions

651.

The correct order of N-compounds in its decreasing order of oxidation states is

  • HNO3, NH4Cl, NO, N2

  • HNO3, NO,NH4Cl, N2

  • HNO3, NO, N2, NH4Cl

  • NH4Cl, N2, NO, HNO3


652.

Which of the following compounds can form a zwitter ion?

  • Aniline

  • Acetanilide

  • Glycine

  • Benzoic acid


653.

Nitration of aniline in strong acidic medium also gives m-nitroaniline because

  • Inspite of substituents nitro group always goes to only m-position.

  • In electrophilic substitution reactions amino group is meta directive.

  • In acidic (strong) medium aniline is present as anilinium ion.

  • In absence of substituents nitro group always goes to m-position.


654.

Which of the following carbocations is expected to be most stable?


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655.

The main product formed in the following reaction is


656.

The correct order of the basic strength of the following are

  • I>II>III>IV

  • IV>II>III>I

  • III>IV>II>I

  • III>II>IV>I


657.

In the reaction,


658.

Which of the following sodium compound/compound (s) are formed when an organic compound containing both nitrogen and sulphur is fused with sodium?

  • Cyanide and sulphide

  • Thiocyanate

  • Sulphite and Cyanide

  • Nitrate and sulphide


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659.

Which of the following is an example of carbylamine reaction?

  • 2Ph NH2 + CS2  (ii) conc. HCl(i) KOH Ph- NCS

  • R - NH2 + HNO2 0 - 5°C R - OH + N2 + HCl

  • Ph - NH2 + CHCl3 + 3KOH (alc.)  ph - NC + 3KCl + 3H2O

  • Ph2 - NH + HONO  Ph2 - N - N= O + H2O


C.

Ph - NH2 + CHCl3 + 3KOH (alc.)  ph - NC + 3KCl + 3H2O

Among all the given options, option c is correct. It correctly represents carbylamine reactions. Other option represents

(a) The following reaction represents Hofmann mustard oil reaction:

2Ph - NH2 + S = C = (ii) conc HCl(i) 2KOH Ph - N = C =S + PhNH3Cl-

(b)The following reaction represents Diazotisation reaction:

R - NH2 + HNO2 0 - 5°C R - OH + N2 + HCl

(d) The foloowing reaction represents Lieber mann;s nitroso reaction:

Ph2NH + HONO Ph- N - N = O + H2O


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660.

C3H9N reacts with Hinsberg reagent and the product is insoluble in alkali but soluble in ether. This nitrogen containing compound is

  • primary amine

  • secondary amine

  • tertiary amine

  • methyl isocyanide


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