With the help of VSEPR theory, explain the shape of: (i) NH3 

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169.

With the help of VSEPR theory, explain the shape of: (i) NH3    (ii) H2O.


(i) NHMolecule: In ammonia molecule, the central nitrogen atom has five electrons in the valence shell. Three of these electrons are mutually shared with the electrons of three hydrogen atoms to form three N- H bonds as shown. 



Hence, the central N atom in NH
3 is surrounded by three bond pairs and one lone pair. The geometry expected for the molecule is tetrahedral since lone pair-bond pair repulsion is more than bond pair-bond pair repulsion. As a result, the lone pair of electrons will repel another pair strongly. Therefore three N–H bonds of NH3 are forced slightly closer.
This leads to decrease in H – N – H bond angles from a normal angle of a tetrahedron (109.5°) to 107°. The most favourable arrangement is distorted tetrahedral i.e. pyramidal. In this, nitrogen atom lies at the centre and three hydrogen atoms occupying the triangular base and the orbital with a lone pair of electrons from the apex of the pyramid.

(ii) H2
O: In a water molecule, the central oxygen atom  has six electrons in the valence shell. Two of these electrons are mutually shared with the electrons of two hydrogen atoms to form two O - H bonds. 


Hence, the central oxygen atom is 
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distortion in the geometry of the molecule. The lone pairs repel the bond pairs more effectively resulting in the decrease of H – O – H angle from 109.5° to 104.5°. The water molecule may be regarded as bent or angular or V-shaped.

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