Long Answer TypeDiscuss the formation of N2 molecule on the basis of MO theory. Predict its:
(i) Bond order
(ii) Magnetic character.
The electronic structure of nitrogen atom is 
Leaving out 4 electrons in the 1s orbital of two nitrogen atoms constituting the molecule (represented as KK), the molecular orbital energy diagram for remaining 10 electrons in nitrogen (N2) is as shown as below:
(i) Electronic configuration:
N2 : [KK (σ2s)2 (σ2s)2 (
2px)1(σ2pz)2]
(i) Bond order : Here Nh = 8 and Na = 2
The two nitrogen atoms in nitrogen molecule are linked by three covalent bonds (i.e. a triple bond).
(ii) Magnetic character: Since all the electrons are paired, nitrogen is diamagnetic.
Write the stability configuration of 
and predict their bond order, stability and magnetic character.
Draw the molecular orbital energy diagram for oxygen molecule (O2) and show that:
(i) It has a double bond
(ii) It has paramagnetic character.
Using a molecular orbital diagram, predict the bond order, stability and magnetic character of O2–,O2+, and 
. Also, write their electronic configurations.
Discuss the relatives stabilities, bond dissociation energies and bond lengths of O2, 
species.
Is the bond order in superoxide ion more or less than in peroxide ion? Explain on the basis of MO theory.
Short Answer TypeUsing bond order show that N2 would be expected to have a triple bond, F2 a single bond and Ne2 no bond.
Show that N2 molecule has a greater bond dissociation energy than N-2 where O2 has lower bond dissociation energy than O+2.
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