Which among the following are having diamagnetic property?(i) B2&

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 Multiple Choice QuestionsMultiple Choice Questions

471.

What are the shapes of ethyne and methane?

  • Square planar and linear

  • Tetrahedral and trigonal planar

  • Linear and tetrahedral

  • Trigonal planar and linear


472.

The bond angle of bond in methoxy methane is

  • 111.7°

  • 109°

  • 108.9°

  • 180°


473.

Which of the following compounds has zero dipole moment?

  • 1, 4-dichlorobenzene

  • 1, 2-dichlorobenzene

  • 1, 3-dichlorobenzene

  • 1-chloro-2-methyl benzene


474.

The number of electrons is the valence shell of the central atom of a molecules is 8. The molecule is

  • BCl3

  • BeH2

  • SCl2

  • SF6


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475.

Which one of the following has longest covalent bond distance?

  • C—C

  • C—H

  • C—N

  • C—O


476.

In which of the following molecules, all bond lengths are not equal?

  • SF6

  • PCl5

  • BCl3

  • CCl4


477.

In which of the following molecules, maximum number of lone pairs is present on the central atom?

  • NH3

  • H2O

  • ClF3

  • XeF2


478.

Match the following:
List - I (Magnetic Property) List - II (Substance)
A. Ferromagnetic 1. O2
B. Antiferromagentic 2. CrO2
C. Ferrimagnetic 3. MnO
D. Paramagnetic

4. Fe3O4

5. C6H6

  • A - 3; B - 2; C - 4; D - 1

  • A - 2; B - 3; C - 4; D - 1

  • A - 1; B - 3; C - 5; D - 4

  • A - 4; B - 2; C - 3; D - 5


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479.

Which one of the following statements is not correct?

  • O3 is used as a germicide.

  • In O3 , O - O bond length is identical with that of molecular oxygen.

  • O3 is an oxidising agent

  • The shape of O3 molecule is angular.


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480.

Which among the following are having diamagnetic property?

(i) B2    (ii) N2    (iii)O2   (iv) C2

  • II, III

  • I ,IV

  • II, IV

  • I, II


C.

II, IV

MO configuration for

(a) O2 = (total electrons = 16 )

=σ1s2*1s2, σ2s2, σ*2s2,σ2p22, πpx2= Πpz1, Π*px1, Π*py1

Thus, has two unpaired electrons and nature is paramagnetic.

(b) N2= ( total electron= 16)

=σ1s2*1s2, σ2s2, σ*2s,πpx2 =Πpy2, σ2z2

Thus, has no unpaired electron and nature is diamagnetic.

(c) C2= (total electron= 12)

=σ1s2*1s2, σ2s, π2px2=Π2py2

Hence, (c) is the correct option (i.e.b,d)


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