If the value of bond order is zero, then
molecule will be stable
molecule will be unstable
molecule will be in ionic state
None of the above
B.
molecule will be unstable
The value of bond order zero means the bonding influence and antibonding influence are equal and as a result there is no net force of attraction, so molecule will be unstable.
Which of the following is a proper match?
Shape | |
A. 0.115 - 0.225 | i. Triangular |
B. 0.225 - 0.414 | ii. Tetrahedral |
C. 0.414 - 0.732 | iii. Cubic |
D. 0.732 - 1 | iv. Octahedral |
A - i; B - ii; C - iv; D - iii
A - iii; B - ii; C - iv; D - i
A - i; B - iii; C - ii; D - iv
A - ii; B - iv; C - i; D - iii
According to MOT which of the following is correct for potassium hexa cyano ferrate (III)?
It is octahedral complex.
t2g orbital contains the e- of metal.
For iron, overlapping between empty orbitals and ligand orbitals takes place.
All of the above
The shape of water molecule according to VSEPR theory, is
octahedral
distorted tetrahedral
trigonal planar
trigonal bipyramidal