Consider the following ions:
(i) Ni2+ (ii) Co2+ (iii) Cr2+ (iv) Fe3+
(Given, at. no. Cr = 24, Fe = 26, Co = 27, Ni = 28)
The correct order of magnetic moment of these ions is
(i) < (ii) < (iii) < (iv)
(iv) < (ii) < (iii) < (i)
(i) < (iii) < (ii) < (iv)
(iii) < (iv) < (ii) < (i)
The electron configuration of the oxide ion is much most similar to the electron configuration of the
sulphide ion
nitride ion
oxygen atom
nitrogen atom
B.
nitride ion
Species having the same number of electrons as in oxide ion, has the same electronic configuration as oxide ion.
In oxide ion (O2-), number of electrons
= 8+2 =10
In sulphide ion (S2-), number of electrons
= 16+2 =18
In nitride ion (N3-), number of electrons
= 7+3 =10
In oxygen atom and nitrogen atom, number of electrons = 8, 7 respectively.
Hence, electronic configuration of