The structure of XeF6 is experimentally determined to be distorte

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 Multiple Choice QuestionsMultiple Choice Questions

881.

The bond angle in NF3 (102.3°) is, smaller than NH3 (107.2°). This is because of

  • large size of F compared to H

  • large size of N compared to F

  • opposite polarity of N in the two molecules

  • small size of H compared to N


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882.

The structure of XeF6 is experimentally determined to be distorted octahedron. Its structure according to VSEPR theory is

  • octahedron

  • trigonal bipyramid

  • pentagonal bipyramid

  • tetragonal bipyramid


C.

pentagonal bipyramid

In XeF6, Xe, the central atom contains, 8 valence electrons. Out of which 6 are utilised with fluorine in bonding (i.e. it contains six bond pairs of electrons) while one pair remains as lone pair.

Thus, the total pairs = 6 + 1 = 7

Hence, its shape is pentagonal bipyramid according to VSEPR theory.


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883.

XeF2 is isostructural with

  • TeF2

  • ICl2-

  • SbCl3

  • BaCl2


884.

In the following electron-dot structure calculate the formal charge from left to right nitrogen atom; N....=N=N.... :

  • -1 , -1 , +1

  • -1 , +1 , -1

  • +1 , -1 , -1

  • +1 , -1 , +1


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885.

The sp3d2 hybridisation of central atom of a molecule would lead to:

  • square planar geometry

  • tetrahedral geometry

  • trigonal bipyramidal geometry

  • octahedral geometry


886.

Which one of the following molecules contain no π-bond?

  • CO2

  • H2O

  • SO2

  • NO2


 Multiple Choice QuestionsShort Answer Type

887.

Why B2 is paramagnetic whereas C2 is dimagnetic?


 Multiple Choice QuestionsMultiple Choice Questions

888.

Dipole moment of  is 1.5 D. The dipole moment of  is

  • 1.5 D

  • 2.25 D

  • 1 D

  • 3 D


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889.

The hybridisation of C2 and C3 of H3C-CH=C=CH-CH3 are:

  • sp , sp3

  • sp2 , sp

  • sp2 , sp2

  • sp , sp


890.

Hybridisation of central atom in NF3 is

  • sp3

  • sp

  • sp2

  • dsp2


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