t / s |
0 |
30 |
60 |
90 |
Ester / mol L–1 |
0.55 |
0.31 |
0.17 |
|
A/mol L–1 |
0.20 |
0.20 |
0.40 |
B/mol L–1 |
0.30 |
0.10 |
0.05 |
r/mol L–1S–1 |
5.07 x 10–5 |
5.07 x 10–5 |
1.43 x 10–4 |
What is the order of the reaction with respect of A and B?
exp.
|
[A]/ |
[B]/M |
Initial rate of formation |
I |
0.1 |
0.1 |
|
II |
0.3 |
0.2 |
7.2 x 10–2 |
III |
0.3 |
0.4 |
2.88 x 10–1 |
IV |
0.4 |
0.1 |
2.40 x 10–2 |
exp.
|
[A]/ |
[B]/M |
Initial rate of formation |
I |
0.1 |
0.1 |
|
II |
- |
0.2 |
4.0 x 10–2
|
III |
0.4 |
0.4 |
- |
IV |
- |
0.2 |
2.0 x 10–2 |
(a) Plot [N2O5] again t.
(b) Find the half life period for the reaction.
(c) Draw a graph between log [N2O5] and t.
(d) What is rate law?
(e) Calculate the rate constant.
(f) Calculate the half life period from K and compare it with (ii).
(b) Time taken for the concentration of N2O5 to change from 1.63 x 10–2 mol L–1 to half the value.
t0.5 = 1420 s [from the graph] (c) Plot of log (N2O5) vs. time.
t |
log10[N2O5] |
0 400 800 1200 1600 2000 2400 2800 3200 3600 |
- 1.7918 - 1.8665 - 1.9431 - 2.0315 - 2.1079 - 2.1938 - 2.2757 - 2.3752 - 2.4559 - 2.5376 |