Radioactivity of a sample (Z = 22) decreases 90% after 10 yr. Wha

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

711.

The half-life of a radioactive element is 10 h. How much will be left after 4 h in 1 g atom sample?

  • 45.6 x 1023 atom

  • 4.56 x 1023 atom

  • 4.56 x 1021 atom

  • 4.56 1020 atom


Advertisement

712.

Radioactivity of a sample (Z = 22) decreases 90% after 10 yr. What will be the half-life of the sample? 

  • 5 yr

  • 2 yr

  • 3 yr

  • 10 yr


C.

3 yr

t = 10 year, t12 = ?

λ = 2.303t log N0Nt 

( radioactivity decreases 90% in 10 year)

∴ N0 = 100 and Nt = 10

Thus, 

λ = 2.30310  log 10010

   = 2.30310

Since, t1/30.693λ

t1/20.693 × 102.303 = 3 years


Advertisement
713.

In the reaction 3A → 2B, rate of reaction +dBdt is equal to

  • -13dAdt

  • -23dAdt

  • +2dAdt

  • -32dAdt


714.

If the volume of the vessel in which the reaction

2NO + O→ 2NO2

is occurring is diminished to 1/3rd of its initial volume. The rate of the reaction will be increased by

  • 3 times

  • 9 times

  • 27 times 

  • 36 times


Advertisement
715.

The half-life period of radioactive element is 140 days. After 560 days, 1 gram of element will reduce to

  • 1/2 g

  • 1/4g

  • 1/8 g

  • 1/16g


716.

In a chemical reaction two reactants takes part. The rate of reaction is directly proportional to the concentration of one of them and inversely proportional to the concentration of the other. The order of reaction is :

  • 0

  • 1

  • 2

  • 4


717.

If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by:

  • t = 6.909/k

  • t = 4.606/k

  • t = 2.303/k

  • t = 0.693/k


Advertisement