[NiCl]42- is paramagnetic while [Ni(CO)4] is diama

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 Multiple Choice QuestionsShort Answer Type

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11. [NiCl]42- is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why?


In Ni(CO)4, Ni is the zero oxidation state whereas in NiCl42–, it is in +2 oxidation state. In the presence of CO ligand, which is strong ligand can paired all electron in Ni(CO), Hence it is a diamagentic in nature. But Cl being a weak ligand is unable to pair up the unpaired electrons. Hence NiCl42- is paramagnetic in nature.
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12. [Fe(H2O)6]3+ is strongly paramagnetic whereas [Fe(CN)6]3- is weakly paramagnetic. Explain.
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13. Explain Co(NH3)63+ is an inner orbital complex whereas Ni(NH3)62+ is an outer orbital complex.
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14.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

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15.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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16. Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.
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17.

Identify the ligands from the following coordination compounds:
(a)    [Co(en)2Cl(NO2)2]
(b)    K[Co(CN)(CO2)(NO)]
(c)    K3[Al(OH)6]
(d)    [Co(H2O)2(NH3)4](OH)3

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18. Write IUPAC name of the following complexes:
(a)    [Fe(H2O)6]SO4
(b)    [Cu(en)
2(NO3)2
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19. Give IUPAC name of the following complexes:
(i) Na2[Fe(CN)5(NO)],       (ii) K2[Zn(CN)4]
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20.

Provide systematic names to the following complexes:
(i)  [Fe(H2O)5(NO)]SO4,
(ii) [Cr(NH3)6]3+
(iii) [Pt(NH3)2Cl2],
(iv) [NiCl4]2–

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