[Co(NH3)6]3+ |
[Ni(NH3)6]2+ |
Electronic configuration of cobalt = d6 |
Electronic configuration of Nickel = d8 |
In this compound oxidation state of cobalt is +3 |
In this compound oxidation state is +2 |
NH3 is a strong field ligand therefore it causes the pairing. Hence, Ni can undergo d2sp3 hybridization. Therefore, it is an inner orbital complex. |
If NH3 causes the pairing, then only one 3d orbital is empty. Thus, it cannot undergo d 2sp3 hybridization. Therefore, it undergoes sp3d 2 hybridization. Hence, it forms an outer orbital complex. |
The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.
Identify the ligands from the following coordination compounds:
(a) [Co(en)2Cl(NO2)2]
(b) K[Co(CN)(CO2)(NO)]
(c) K3[Al(OH)6]
(d) [Co(H2O)2(NH3)4](OH)3
Provide systematic names to the following complexes:
(i) [Fe(H2O)5(NO)]SO4,
(ii) [Cr(NH3)6]3+
(iii) [Pt(NH3)2Cl2],
(iv) [NiCl4]2–