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FeSO 4 does not form any complex with (NH 4 ) 2 SO 4 . Instead, .they form a double salt, FeSO 4 , (NH 4 ),SO 4 .6H 2 O which dissociates completely into ions. FeSO 4 +6H 2 O+(NH 4 ) 2 SO 4 --> FeSO 4 .(NH 4 ) 2 SO 4 .H 2 O But CuSO 4 combines with NH 3 to form the complex [Cu(NH 3 ) 4 ]SO 4 in which the complex ion [Cu(NH 3 ) 4 ] 2+ does not dissociate to give Cu 2+ ions. CuSO 4 +4NH 3 +5H 2 O-->[Cu(NH3)4]SO 4 .5H 2 O

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Coordination Compounds

Short Answer Type

31.

Illustrate the geometrical isomers of [Pt(NH₃)₄Cl₂]⁺.

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32. FeSO₄ solution mixed with (NH₄)₂SO₄ solution in 1 : 1 molar ratio gives the test of Fe²⁺ ion but CuSO₄ solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu²⁺ ion. Explain why?

FeSO₄ does not form any complex with (NH₄)₂SO₄. Instead, .they form a double salt, FeSO₄, (NH₄),SO₄.6H₂O which dissociates completely into ions.

FeSO₄ +6H₂O+(NH₄)₂SO₄ --> FeSO₄.(NH₄)₂SO₄.H₂O

But CuSO₄ combines with NH₃ to form the complex [Cu(NH₃)₄]SO₄ in which the complex ion [Cu(NH₃)₄]²⁺does not dissociate to give Cu²⁺ions.

CuSO₄ +4NH₃ +5H₂O-->[Cu(NH3)4]SO₄.5H₂O

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