What is the oxidation state of platinum in [Pt(en)2Cl2]?
Oxidation state of platinum
Pt = x
charge of ethylene diamine is (en)= 0
charge of chlorine is Cl=(-1)
thus,
x+0+(-1)x2 =0
x+(-2) =0
x=2
In a geometry of [PtCl4]2– is square planar, what orbitals of platinum are involved in the bonding?