Short Answer TypeOn adding NaOH to ammonium sulphate, a colourless gas with pungent odour is evolved, which forms a blue-coloured complex with Cu2+ ion. Identify the gas.
When a co-ordination compound CrCl3.6H2O is mixed with AgNO3, 2 moles of AgCl are precipitated per mole of the compound. Write
(i)Structural formula of the complex.
(ii)IUPAC name of the complex.
(a) For the complex [Fe(CN)6]3–, write the hybridization type, magnetic character and spin nature of the complex. (At. number : Fe = 26).
(b) Draw one of the geometrical isomers of the complex [Pt(en)2Cl2]2+ which is optically active.
When coordination compound CoCl3.6NH3 is mixed with AgNO3, 3molesof AgCl is precipitated per mole of the compound. write
i) Structural formula of the complex
ii) IUPAC name of the complex
a) For the complex [Fe(H2O)6]3+, write the hybridization,magnetic character and spin of the complex.(At.number: Fe=26).
b) Draw one of the geometrical isomers of the complex [Pt(en)2Cl2]2+ which is optically inactive.
Write the state of hybridization, the shape and the magnetic behaviour of the following complex entities:
(i) [Cr (NH3)4 Cl2] Cl
(ii) [Co (en) 3] Cl3
(iii) K2 [Ni (CN) 4](i) Write the IUPAC name of the complex [Cr(NH3)4Cl2]Cl.
(ii) What type of isomerism is exhibited by the complex [Co(en)3]3+?
(en = ethane-1,2-diamine)
(iii) Why is [NiCl4]2− paramagnetic but [Ni(CO)4] is diamagnetic?
(At. nos. : Cr = 24, Co = 27, Ni = 28)
(i) The IUPAC name of the complex [Cr(NH3)4Cl2]Cl is Tetraamminedichlorochromium(III) chloride.
(ii) The complex [Co(en)3]3+ exhibits optical isomerism. Its optical isomers are shown below.
(iii) In [NiCl4]2−, the oxidation state of Ni is +2. Chloride is a weak field ligand and does not cause pairing up of electrons against the Hund's rule of maximum multiplicity. As a result, two unpaired electrons are present in the valence d-orbitals of Ni which impart paramagnetic character to the complex. On the other hand, carbonyl is a strong field ligand and causes pairing up of electrons against the Hund's rule of maximum multiplicity. As a result, no unpaired electrons are present and hence, the complex is diamagnetic.
Why a solution of [Ni(H2O)6]2+ is green while a solution of [Ni(CN)4]2– is colourless? (At. no. of Ni = 28)
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