Write the hybridisation and number of unpaired electrons in the complex [CoF6]3-.
Atomic No. of Co = 27
The number of unpaired electrons in[NiCl4]2-, Ni(CO)4 and (Cu(NH3)4]2+ respectively are
0, 2, 1
2, 0, 1
0, 2, 1
2, 2, 0
B.
2, 0, 1
Configuration for metal (M) in various complex.
Ni2+ has 2 unpaired electrons.
Ni0 has zero unpaired electrons with sp3-hybridisation.
Cu2+ has one unpaired electron with dsp2-hybridisation.
Therefore, number of unpaired electrons is (2, 0, 1).
The pair having the same magnetic moment is:
[At. No. : Cr=24, Mn=25, Fe=26, Co=27]
[Cr(H2O)6 ]2+ and [Fe(H2O)6 ]2+
[Mn(H2O)6 ]2+ and [Cr(H2O)6 ]2+
[CoCl4 ]2− and [Fe(H2O)6 ]2+
[CoCl4 ]2− and [Fe(H2O)6 ]2+