Multiple Choice QuestionsThe IUPAC name of the complex ion formed when gold dissolves in aqua-regia is
tetrachloridoaurate (III)
tetrachloridoaurate (I)
tetrachloridoaurate (II)
dichloridoaurate (III)
Which of the following will be able to show geometrical isomerism?
MA3B - Square planar
MA2B2 - tetrahedral
MABCD- saquare planar
MABCD- tetrahedral
C.
MABCD- saquare planar
Tetrahedral complexes do not show geometrical isomensm because relative position of unidentate ligands attached to central metal atom are same with respect to each other .So, options (b) and (d) are not correct.
Square planar complex MA3B (option (a) do not show geometrical isomerism because the possible spatial arrangement are equivalent. Squar planar complex MABCD type form three isomers (cs-transisomerism ), two of these are cis and one is trans.
The complex formed when Al2O3 is leached from bauxite using conc. NaOH solution is,
Na[Al(OH)4]
NaAl2O4
Na[Al(OH)3]
Na2AlO2
The number of isomers possible for the octahedral complex [CoCl2(en)(NH3)2]+ is
two
three
no isomer
four isomers
The complex ion having minimum magnitude of Δ° (CFSE) is
[Cr(CN)6]3-
[Co(CN3)6]3+
[Co(Cl)6]3+
[Cr(H2O)6]3+
As per IUPAC norms, the name of the complex [Co(en)2(ONO)Cl]Cl is
chlorido bis (ethane-1, 2-diamine) nitro-O-cobalt (III) chloride
chlorido bis (ethylenediamine) nitro-O-cobalt (III) chloride
chlorido di (ethylenediamine) nitrocobalt (III) chloride
chloro ethylenediaminenitr-O-cobalt (III) chloride
Square planar complex of the type MAXBL (where A, B,X and L) are unidenate ligands) shows following set of isomers.
two cis and one trans
two trans and one cis
two cis and two trans
three cis and one trans
The formula of potash alum is :
K2SO4.Al2(SO4)3.24H2O
K2SO4.Al2(SO4)3.18H2O
K2SO4.(NH4)2SO4.18H2O
Na2SO4.Al2(SO4)3.24H2O
According to crystal field theory, the M-L bond in a complex is
partially covalent
purely ionic
purely covalent
purely coordinate
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