182.
Write the Nernst equation and emf of the following cells at 298 k.
Fe(s) | Fe2+ (0.001 M) || H+ (1M) | H2 (g) (1 bar) | Pt(s)
Anode reaction:
Cathode reaction:
Overall cell reaction:
The Nernst equation for Ecell at 298 k can be written as:
= 0.44 – 0.0295 (–3) = 0.44 – 0.0885 = 0.5285 V
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