Short Answer TypeWe have given that
current = 0.5 ampere
weight of H2 (W) = ?
t = 1 hour = 3600 sec,
Z = 0.00001.
W = Z x c x t
= 0.00001 x 0.5 x 3600 g = 0.018 g
2g or H2 at STP occupies = 22.4 litres
0.018 g of H2 at STP occupies
Hence, Volume of H2 produced at STP = 0.2016 litres.
Long Answer TypeHow much charge is required for the following reduction of
(i) 1 mol of Al3+ to Al
(ii) 1 mol of Cu2+ to Cu
(iii) 1 mol of MnO4– to Mn2+
Short Answer TypeLong Answer TypeA Cell is prepared by dipping a copper rod in 0.01 M copper sulphate solution, and zinc rod in 0.02 M ZnSO4 solution. The standard reduction potentials of copper and zinc are + 0.34 V and – 0.76 V respectively.
(a) What will be the cell reaction?
(b) How will the cell be represented?
(c) What will be the emf. of the cell?
Write the Nernst equation and calculate the emf of the following cell at 298 K:
Pt(s) | Br2 (l) Br– (0.01M) || H+ (0.03 M) | H2(g) (1 bar) | Pt(s)
Given E°Br2/Br– = + 1.08 V
Br2 / Br–
Short Answer Type
Switch
