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 Multiple Choice QuestionsShort Answer Type

291. Determine the equilibrium constant of the reaction at 298 K.
2Fe3++Sn2+  2Fe2++Sn4+
From the obtained value of the equilibrium constant, predict whether Sn2+ ions can reduce Fe3+ to Fe2+ quantitatively or not.
E°Sn4+/Sn2+ = 0.15 V and E°Fe3+/Fe2+ = +0.77 V
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292. Calculate the equilibrium constant for the reaction at 298 K
                      Cu(s) + Cl2(g)  CuCl2(aq)
Given: E°Cu2+/Cu = 0.34  V;  E°Cl2+/Cl- = 1.36 V,  R = 8.314 J K-1 mol-1
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293. Calculate the equilibrium constant Kc for the reaction at 298 K.
                        3Sn4+ + 2 Cr   3Sn2++2Cr3+
(Given E°Sn4+/Sn2+ = 0.15 V;  E°Cr3+/Cr = -074 V). = 0.34 V;
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294. Calculate the equilibrium constant for the cell reaction:
                           4Br-+O2+4H+2Br2+2H2O
(Given E°cell = 0.16)


we have given that 
E0 = 0.16
log KC = nE°cell0.0591   E°cell = 0.16 V,      n = 4

log KC = (4)×(0.16 V)(0.0591 V) = 10.8      KC = Antilog 10.8 = 6.31 × 1010
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 Multiple Choice QuestionsLong Answer Type

295. Calculate the potential (emf.) of the cell
Cd | Cd2+ (0.10 M) || H+(0.20 M) | Pt, H2 (0.5 atm)
(Given : E° Cd2+ / Cd = – 0.403 V, R = 8.314 K–1 K–1 mol–1, F = 96500 C mol–1
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 Multiple Choice QuestionsShort Answer Type

296. Calculate ΔG° for the reaction                   Cu2+(aq)+Fe(s)  Fe2+(aq) + Cu(s)(Given E°Cu2+/Cu = 0.34 V,   E°Fe3+/Fe = -0.44 V,  F = 96500 e mol-1)
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297. The standard electrode potential for Daniell cell is 1.1 V. Calculate the standard Gibbs energy for the reaction:
           Zn(s) + Cu2+(aq)      Zn2+(aq) + Cu(s)
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298.

Calculate the Δr G° and the equilibrium constant for the reaction
2Cr(s) + 3Cd2+ (aq) 2Cr3+ (aq) + 3Cd(s)
(Given E°Cr3+/Cr = 0.74 V, E°Cd2+/ Cd = – 0.40 V)

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299.

Calculate the cell e.m.f. and ΔG for the cell reaction at 298 K for the cell
Zn(s) | Zn2+ (0.0004 M) || Cd2+(0.2 M) | Cd(s)
(Given E°Zn2+/Zn = 0.763 V, E°cd 2+ / cd = 0.403 Vat 298 K, F = 96500 C mol–1)

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300. Calculate the cell emf and AG for the cell rection at 25°C for the cell
Zn(s) | Zn2+ (0.0004 M) || Cd2+ (0.2 M) | Cd(s) E° values at 25°C, Zn2+/Zn = – 0.763 V, Cd2+ / Cd = – 0.403 V F = 96500 C mol–1, R = 8.314 J K–1 mol–1
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