Following reactions occur at cathode during the electrolysis of aqueous silver chloride solution:
Ag+ (aq) + e- → Ag(s) E° = +0.80 V
H+ (aq) + e- → 1/2 H2 (g) E° = 0.00 V
On the basis of their standard reduction electrode potential (E°) values, which reaction is feasible at the cathode and why?
We have given:
Ag+ (aq) + e- → Ag(s) E° = +0.80 V
H+ (aq) + e-→ 1/2 H2 (g) E° = 0.00 V
The relationship between the standard free energy change and emf of a cell reaction is given by
∆ G = – nFE(cell)
Thus, the more positive the standard reduction potential of a reaction, the more negative is the standard free energy change associated with the process and, consequently, the higher is the feasibility of the reaction.
Since E 0 Ag+/Ag has a greater positive value than E0 H+ /H, the reaction which is feasible at the cathode is given by
Ag+ (aq) + e- → Ag(s)
Define limiting molar conductivity. Why conductivity of an electrolyte solution decreases with the decrease in concentration?
Calculate emf of the following cell at 25 °C:
Fe | Fe2+(0.001 M) || H+ (0.01 M) | H2 (g) (1 bar) | Pt(s)
E°(Fe2+ | Fe) = –0.44 V E°(H+ | H2 ) = 0.00 V
The resistance of a conductivity cell filled with 0.1 mol L-1 KCl solution is 100 . If the resistance of the same cell when filled with 0.02 mol L-1 KCl solution is 520 , calculate the conductivity and molar conductivity of 0.02 mol L-1 KCl solution. The conductivity of 0.1 mol L-1 KCl solution is 1.29x 10-2 -1cm-1
State Faraday's first law of electrolysis. How much charge in terms of Faraday is required for the reduction of 1 mol of Cu2+ to Cu.
Calculate emf of the following cell at 298 K: Mg(s) | Mg2+(0.1 M) || Cu2+ (0.01) | Cu(s)
[Given E0 cell = +2.71 V, 1 F = 96500 C mol-1]
The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm-1. Calculate its molar conductivity?
a) What type of a battery is the lead storage battery? Write the anode and the cathode reactions and the overall reaction occurring in a lead storage battery when current is drawn from it.
(b) In the button cell, widely used in watches, the following reaction takes place
Determine E° and G° for the reaction