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 Multiple Choice QuestionsMultiple Choice Questions

371.

During electrolysis of molten NaCl, some water was added. What will happen?

  • Electrolysis will stop

  • Hydrogen will be evolved

  • Some amount of caustic soda will be formed

  • A fire is likely


372.

The role of fluorspar, which is added in small quantities in the electrolytic reduction of alumina dissolved in fused cryolite is

  • as a catalyst

  • to make fused mixture conducting

  • to lower the melting temperature of the mixture

  • to decrease the rate of oxidation of carbon at anode


373.

At temperature of 298K, the emf of the following electrochemical cell,

Ag (s) | Ag+ (0.1 M)|| Zn2+ (0.1 M) | Zn (s)

will be (Given, E°cell = -1.562 V)

  • -1.532 V

  • -1.503 V

  • 1.532 V

  • -3.06 v


374.

The quantity of electricity needed to separately electrolyze 1 M solution of ZnSO4 , AlCl3 and AgNO3 completely is in the ratio of

  • 2 : 3 :1

  • 2 : 1 : 1

  • 2 : 1:3

  • 2 : 2 : 1


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375.

The two half-cell reactions of an electrochemical cell is given as

Ag+ + e-  Ag;                   E°Ag+/Ag=-0.3995 V        Fe2+ Fe3+ + e- ;     E°Fe3+ /Fe2+= -0.7120 V 

The value of cell EMF will be

  • -0.3125 V

  • 0.3125 V

  • 1.114 V

  • -1.114V


376.

At 25C, the molar conductance of 0.007 M hydrofluoric acid is 150 mho cm2mol-1and its λ°m = 500 mho cm2mol-1. The value of the dissociation constant of the acid at the given concentration at 25°C is

  • 7 X 10-4 M

  • 7 X 10-5 M

  • 9 X 10-3 M

  • 9 X 10-4 M


377.

The formal potential of Fe3+ /Fe4+ in a sulphuric acid and phosphoric acid mixture (E° = + 0.61 V) is much lower than the standard potential (E° = + 0. 77 V). This is due to

  • formation of the species [FeHPO4]+

  • lowering of potential upon complexation

  • formation of the species [FeSO4]+

  • high acidity of the medium


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378.

A conductivity cell has been calibrated with a 0.01 M 1 : 1 electrolyte solution (specific conductance, k = 1.25 × 10-3S cm-1) in the cell and the measured resistance was 800 Ω at 25°C. The cell constant will be

  • 1.02 cm-1

  • 0.102 cm-1

  • 1.00 cm-1

  • 0.5 cm-1


C.

1.00 cm-1

Given, κ = 1.25 × 10-3 S cm-1

ρ = 1κ = 11.25 × 10-3 S-1 cm

From, R = ρlA

800 = 11.25 × 10-3 × lA (where, lA = cell constant)

 lA = 800 × 1.25 × 10-3 = 1cm-1


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379.

Equivalent conductivity at infinite dilution for sodium-potassium oxalate [(COO-)2 Na+K+] will be [given molar conductivities of oxalate, K+ and Na+ ions at infinite dilution are 148.2, 50.1, 73.5 S cm mol' respectively]

  • 271.8 S cm2 eq-1

  • 67.95 S cm2 eq-1

  • 543.6 S cm2 eq-1

  • 135.9 S cm2 eq-1


380.

The standard reduction potential E° for half-reaction are

Zn → Zn2+ + 2e- ; E° = + 0.76 V

 Fe → Fe2+ + 2e- ; E° = + 0.41 V

The EMF of the cell reaction

Fe2+ + Zn → Zn2+ + Fe is

  • -0.35 V

  • +0.35 V

  • +1.17 V

  • -1.17 V


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