During electrolysis of molten NaCl, some water was added. What will happen?
Electrolysis will stop
Hydrogen will be evolved
Some amount of caustic soda will be formed
A fire is likely
The role of fluorspar, which is added in small quantities in the electrolytic reduction of alumina dissolved in fused cryolite is
as a catalyst
to make fused mixture conducting
to lower the melting temperature of the mixture
to decrease the rate of oxidation of carbon at anode
At temperature of 298K, the emf of the following electrochemical cell,
Ag (s) | Ag+ (0.1 M)|| Zn2+ (0.1 M) | Zn (s)
will be (Given, E°cell = -1.562 V)
-1.532 V
-1.503 V
1.532 V
-3.06 v
The quantity of electricity needed to separately electrolyze 1 M solution of ZnSO4 , AlCl3 and AgNO3 completely is in the ratio of
2 : 3 :1
2 : 1 : 1
2 : 1:3
2 : 2 : 1
The two half-cell reactions of an electrochemical cell is given as
The value of cell EMF will be
-0.3125 V
0.3125 V
1.114 V
-1.114V
At 25C, the molar conductance of 0.007 M hydrofluoric acid is 150 mho cm2mol-1and its = 500 mho cm2mol-1. The value of the dissociation constant of the acid at the given concentration at 25°C is
7 X 10-4 M
7 X 10-5 M
9 X 10-3 M
9 X 10-4 M
The formal potential of Fe3+ /Fe4+ in a sulphuric acid and phosphoric acid mixture (E° = + 0.61 V) is much lower than the standard potential (E° = + 0. 77 V). This is due to
formation of the species [FeHPO4]+
lowering of potential upon complexation
formation of the species [FeSO4]+
high acidity of the medium
A conductivity cell has been calibrated with a 0.01 M 1 : 1 electrolyte solution (specific conductance, k = 1.25 × 10-3S cm-1) in the cell and the measured resistance was 800 at 25°C. The cell constant will be
1.02 cm-1
0.102 cm-1
1.00 cm-1
0.5 cm-1
Equivalent conductivity at infinite dilution for sodium-potassium oxalate [(COO-)2 Na+K+] will be [given molar conductivities of oxalate, K+ and Na+ ions at infinite dilution are 148.2, 50.1, 73.5 S cm mol' respectively]
271.8 S cm2 eq-1
67.95 S cm2 eq-1
543.6 S cm2 eq-1
135.9 S cm2 eq-1
The standard reduction potential E° for half-reaction are
Zn → Zn2+ + 2e- ; E° = + 0.76 V
Fe → Fe2+ + 2e- ; E° = + 0.41 V
The EMF of the cell reaction
Fe2+ + Zn → Zn2+ + Fe is
-0.35 V
+0.35 V
+1.17 V
-1.17 V
B.
+0.35 V
Zn → Zn2+ + 2e- ; E = +0.76 V or E = -0.76 V
Fe → Fe2+ + 2e- ; E = + 0.41 V or E = -0.41 V
= -0.41 - (0.76)
= + 0.35 V