The standard reduction potential for Zn2+ /Zn, Ni2+ /Ni and Fe2+&

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 Multiple Choice QuestionsMultiple Choice Questions

421.

In the cell represented by

Pb(s)|Pb2+(1M) || Ag+(1M)| Ag(s), the reducing agents is

  • Pb2+

  • Pb

  • Ag

  • Ag+


422.

What is the SI unit of conductivity?

  • Sm

  • Sm-1

  • Sm2

  • Sm-2


423.

Consider the equilibrium obtained by electrically connecting zinc-amalgam Zn(Hg) and HgO electrodes in mercury cell,

Au(Hg) + HgO (s)  ZnO (s) + Hg (l)

Under this equilibrium, what is the relation between the potential of the Zn(Hg) and HgO electrodes measured against the standard hydrogen electrode?

  • Zn(Hg) electrode potential is equal to HgO electrode potential.

  • Zn(Hg) electrode potential is more than HgO electrode potential.

  • HgO electrode potential is more than Zn(Hg) electrode.

  • Cell voltage at above said equilibrium is 1.35 V


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424.

The standard reduction potential for Zn2+ /Zn, Ni2+ /Ni and Fe2+ /Fe are respectively -0.76, -0.23 and -0.44 V. The reaction X + Y2+ → X2+ + Y will have more negative G value when X and Y are

  • X = Ni; Y = Fe

  • X = Ni; Y = Zn

  • X = Fe; Y = Zn

  • X = Zn; Y = Ni


D.

X = Zn; Y = Ni

Given, 

Zn2+/ Zn = -0.76 V

Ni2+/ Ni   = -0.23 V

Fe2+/ Fe  = -0.44 V

and relation,

X + Y2+ → X2+ + Y, means

X is oxidised to X2+ (acts as anode)

Y2+ is reduced to Y (acts as cathode)

Also, Ecell° = EC° - EA°

Now, in option d

X = Zn; Y = Ni

Ecell° = -0.23 - (-0.76) 

      = +0.53

 G° = -nFE° = (-2 × 0.53)F               = -1.06 F

Therefore, among all the given options, option D is the correct one.


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425.

The standard electrode potentials of Zn and Ni respectively are - 0.76 V and - 0.25 V. Then the standard emf of the spontaneous cell by coupling these under standard conditions is

  • +1.01 V

  • -0.51 V

  • +0.51 V

  • +0.25 V


426.

How many moles of platinum will be deposited on the cathode when 0.60 F of electricity is passed through a 1.0 M solution of Pt4+?

  • 0.60 mol

  • 0.15 mol

  • 0.30 mol

  • 0.45 mol


427.

A 250 W electric bulb of 80% efficiency emits a light of 6626 Å wavelength. The number of photons emitted per second by the lamp is (h = 6.636 x 10-34 Js)

  • 1.42 × 1017 

  • 2.18 × 1016 

  • 6.66 × 1020 

  • 2.83 × 1016 


428.

Consider the following elecrolytic cells

(i) M (s) | M2+ (aq), 0.1 M || X2+ (aq), 0.01 M | X (s)

(ii) M (s) | M2+ (aq), 0.1 M || X2 (aq), 0.01 M | X (s)

(iii) M (s) | M2+ (aq), 0.1 M || X2 (aq), 0.01 M | X (s)

The cell EMF of the above cells are E1, E2 and E3 respectively. Which one of the following is true?

  • E3 > E2 > E1

  • E1 > E2 > E3

  • E2 > E3 > E1

  • E1 > E3 > E2


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429.

When the total cell emf of a volatic cell is greater than zero, which of the following is true about the reaction quotient Q and free energy change G for the cell reaction?

  • Q is less than one and G is greater than zero

  • Q is greater than one and G is greater than zero

  • Q is greater than one and G is less than zero

  • Q is zero and G is greater than zero


430.

In dry cell, what acts as a negative electrode?

  • Zinc

  • Graphite

  • Ammonium chloride

  • Manganese dioxide


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