The emf (in V) of a Daniell cell containing 0.1 M ZnSO4 and

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 Multiple Choice QuestionsMultiple Choice Questions

471.

A solution of concentration C g equiv/L has a specific resistance R. The equivalent conductance of the solution is

  • R/C

  • C/R

  • 1000/RC

  • 1000R/C


472.

For the following cell reaction,

Ag | Ag+ | AgCl | Cl | Cl2, Pt

Gf° (AgCl) = - 109 kJ/ mol

Gf° (Cl) = -129 kJ/ mol

Gf°(Ag+) = 78 kJ/ mol

E° of the cell is

  • -0.60 V

  • 0.60 V

  • 6.0 V

  • None of these


473.

Which one of the following is most effective in causing the coagulation of an As2S3 sol?

  • KCl

  • AlCl3

  • MgSO4

  • K3Fe(CN)6


474.

At a certain temperature and at infinite dilution, the equivalent conductances of sodium benzoate, hydrochloric acid and sodium chlonde are 240, 349 and 229 ohm-1 cm2equiv-1 respectively. The equivalent conductance of benzoic acid in ohm-1 cm2equiv-1 at the same conditions is

  • 80

  • 328

  • 360

  • 408


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475.

Match the following-
List - I List - II
A. Potential of hydrogen electrode at pH = 10 i. 0.76 V
B. Cu2+  | Cu ii. 0.059
C. Zn | Zn2+  iii. -0.591 V
D. 2.303 RTF

iv. 0.037 V

v. -0.76 V

  • A - iii; B - i; C - ii; D - v

  • A - ii; B - v; C - i; D - iv

  • A - iii; B - iv; C - i; D - ii

  • A - v; B - i; C - iv; D - ii


476.

If the values of  of NH4Cl, NaOH and NaCl are 130, 217 and 109 ohm-1 cm2 equiv-1 respectively, the  of NH4OH in ohm-1 cm2 equiv-1 is

  • 238

  • 196

  • 22

  • 456


477.

During the electrolysis of copper sulphate aqueous solution using copper electrode, the reaction taking place at the cathode is

  • Cu → Cu2+ (aq) + 2e-

  • Cu2+ (aq) + 2e- → Cu (s)

  • H+ (aq) + e- → 12 H2 (g)

  • SO42- (aq) → SO3 (g) + 12O2 (g) + 2e-


478.

The extent of charge of lead accumulator is determined by

  • amount of PbSO4 in the battery

  • amount of PbO2 in the battery

  • specific gravity of H2SO4 of the battery

  • amount of Pb in the battery


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479.

The emf (in V) of a Daniell cell containing 0.1 M ZnSO4 and 0.01 M CuSO4 solutions at their respective electrodes is

(ECu2+/Cu°= + 0.34 V; EZn2+/ Zn° = -0.76V)

  • 1.10

  • 1.16

  • 1.13

  • 1.07


D.

1.07

ECu2+/Cu°= + 0.34 V; EZn2+/ Zn° = -0.76V=+ 0.34-(- 0.76) V =1.1VFurther Ecell= Ecell°- 0.059nlog [product][reactants]For the reaction,CuSO4 + Zn  ZnSO4+ CuOr Cu2+ + Zn Zn2+ + Cu Ecell= Ecell°- 0.0592log  Zn2+Cu2+= 1.1- 0.0592log0.10.01= 1.1- 0.0592log 10= 1.1-0.0295 × 1= 1.07V


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480.

The role of copper diaphragm in Whytlaw-Gray's method is

  • preventing the corrosion of electrolytic cell

  • preventing the mixing of H2 and F2

  • as anode

  • as cathode


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