Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Equilibrium

Short Answer Type

21. Under what condition, a reversible process becomes irreversible ?

212 Views

22. Give two important characteristics of the equilibrium constant.

119 Views

23. Give the equilibrium constant for the following equilibrium in terms of partial pressures:

straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space 2 NH subscript 3 left parenthesis straight g right parenthesis.

127 Views

24. What is the relation between K_p and K_c?

179 Views

25. Under what condition in a reversible reaction is K_p = K_c?

199 Views

26. Predict which of the following reaction will have appreciable concentration of reactants and products:

left parenthesis straight a right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight C space equals space 5 space cross times space 10 to the power of negative 39 end exponent left parenthesis straight b right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space plus space 2 NO left parenthesis straight g right parenthesis space space space leftwards harpoon over rightwards harpoon space 2 NO subscript 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight c space equals space 3.7 space cross times space 10 to the power of negative 8 end exponent left parenthesis straight c right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space plus space 2 NO subscript 2 left parenthesis straight g right parenthesis space leftwards harpoon over rightwards harpoon space space 2 NO subscript 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight c space equals space 1.8

541 Views

27. PCl₅, PCl₃ and Cl₂ are at equilibrium at 500K and having concentration 1·59M PCl₃, 1·59M Cl₂ and 1·41 M PCl₅. Calculate K_c for the reaction:

<pre>uncaught exception: <b>Http Error #404</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/HttpImpl.class.php line 61<br />#0 [internal function]: com_wiris_plugin_impl_HttpImpl_0(Object(com_wiris_plugin_impl_HttpImpl), NULL, 'http://www.wiri...', 'Http Error #404') #1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/php/Boot.class.php(769): call_user_func_array('com_wiris_plugi...', Array) #2 [internal function]: _hx_lambda->execute('Http Error #404') #3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/haxe/Http.class.php(532): call_user_func_array(Array, Array) #4 [internal function]: haxe_Http_5(true, Object(com_wiris_plugin_impl_HttpImpl), Object(com_wiris_plugin_impl_HttpImpl), Array, Object(haxe_io_BytesOutput), true, 'Http Error #404') #5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/php/Boot.class.php(769): call_user_func_array('haxe_Http_5', Array) #6 [internal function]: _hx_lambda->execute('Http Error #404') #7 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/HttpImpl.class.php(27): call_user_func_array(Array, Array) #8 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/haxe/Http.class.php(444): com_wiris_plugin_impl_HttpImpl->onError('Http Error #404') #9 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/haxe/Http.class.php(458): haxe_Http->customRequest(true, Object(haxe_io_BytesOutput), NULL, NULL) #10 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/HttpImpl.class.php(40): haxe_Http->request(true) #11 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(80): com_wiris_plugin_impl_HttpImpl->request(true) #12 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array) #13 {main}</pre>

338 Views

28. A quantity of PCl₅ was heated in a 10 litre vessel at 250°C.

PCl subscript 5 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space PCl subscript 3 left parenthesis straight g right parenthesis plus space Cl subscript 2 left parenthesis straight g right parenthesis.

At equilibrium the vessel contains 0.1 mole of

PCl subscript 5 comma

0.20 mole of

PCl subscript 3

and 0.20 mole of Cl₂. What is the value of equilibrium constant of the reaction?

872 Views

29. At equilibrium, the concentration of N₂ = 3·0 × 10^–3 M, O₂ = 4·2 × 10^–3 M and NO = 2·8 × 10^–3 M in a sealed vessel at 800K. What will be K_c for the reaction:

straight N subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis

321 Views

30. The following concentrations were obtained for the formation of NH₃ from N₂and H₂ at equilibrium at 500K. [N₂] = 1·5 × 10^–2 M, [H₂] = 3·0 × 10^–2M and [NH₃] = 1·2 × 10^–2 M. Calculate the equilibrium constant.

The reaction is

We have given,
[N₂] = 1·5 × 10^–2 M
[H₂] = 3·0 × 10^–2M
[NH₃] = 1·2 × 10^–2 M

Applying the law of chemical equilibrium, we have

Putting the values in expression (1), we have

860 Views

Previous Year Papers

Test Series

Test Yourself

Short Answer Type

30. The following concentrations were obtained for the formation of NH3 from N2and H2 at equilibrium at 500K. [N2] = 1·5 × 10–2 M, [H2] = 3·0 × 10–2M and [NH3] = 1·2 × 10–2 M. Calculate the equilibrium constant.

30. The following concentrations were obtained for the formation of NH₃ from N₂and H₂ at equilibrium at 500K. [N₂] = 1·5 × 10^–2 M, [H₂] = 3·0 × 10^–2M and [NH₃] = 1·2 × 10^–2 M. Calculate the equilibrium constant.