State and explain the law of mass action. from Chemistry Equili

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 Multiple Choice QuestionsShort Answer Type

61. Vapour pressures of water, acetone and ethanol at 293K are 2.34kPa, 12.36kPa and 5.85 kPa respectively. Which of these has the lowest and the highest boiling point? At 293K which of these evaporates least in a sealed container before equilibrium is established?
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 Multiple Choice QuestionsLong Answer Type

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62. State and explain the law of mass action.


The law of mass action (Guldberg and Waage) may be stated as:

The rate at which a substance reacts is directly proportional to its active mass (molar concentration) and the rate of chemical reaction is proportional to the product of active masses of the reacting substances.
By the term active mass, we mean molar concentration or number of moles per litre. The active mass of A is denoted as [A].

Consider a simple reaction A  Product
According to the law of mass action,
Rate of reaction  
where [A] represents the active mass of A, k is proportionality constant known as velocity constant. The velocity constant is also called velocity co-efficient or rate constant or specific reaction rate.



According to the law of mass action,
Rate of the reaction 



For a general reaction,



According to the law of mass action, 

Rate of the reaction = 

Hence the law of mass action may also be stated as the rate of the reaction is proportional to the product of the active masses (or molar concentration) of reactants with each active mass raised to the power equal to the number of molecules of the respective reactants participating in the reaction.

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63. Apply the law of mass action to a reversible reaction and state the law of chemical equilibrium.
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 Multiple Choice QuestionsShort Answer Type

64. The equilibrium constant expression for a gas reaction is,
         straight K subscript straight c space equals space fraction numerator open square brackets NH subscript 3 close square brackets to the power of 4 space open square brackets straight O subscript 2 close square brackets to the power of 5 over denominator open square brackets NO close square brackets to the power of 4 space open square brackets straight H subscript 2 straight O close square brackets to the power of 6 end fraction
Write the balanced chemical equation corresponding to this expression.

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65.

How is equilibrium constant expressed when the reaction is carried in the gaseous phase ?

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 Multiple Choice QuestionsLong Answer Type

66. Derive the relation between Kp and Kc.
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67.

Under what conditions:
(i) Kp = Kc   (ii) K> Kc     (iii) Kp< Kc

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 Multiple Choice QuestionsShort Answer Type

68.

Write the expressions for equilibrium constant for the reactions:
left parenthesis straight i right parenthesis space straight H subscript 2 left parenthesis straight g right parenthesis space plus space space straight I subscript 2 left parenthesis straight g right parenthesis space space space space space rightwards harpoon over leftwards harpoon space space 2 HI left parenthesis straight g right parenthesis
left parenthesis ii right parenthesis space straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space 2 NH subscript 3 left parenthesis straight g right parenthesis
left parenthesis iii right parenthesis space PCl subscript 5 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space PCl subscript 3 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis

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69. Write equilibrium constant expression for the following:
left parenthesis straight i right parenthesis space Fe to the power of 3 plus end exponent left parenthesis aq right parenthesis space plus space SCN to the power of minus left parenthesis aq right parenthesis space space rightwards harpoon over leftwards harpoon space space FeSCN to the power of 2 plus end exponent left parenthesis aq right parenthesis
left parenthesis ii right parenthesis space 3 Fe left parenthesis straight s right parenthesis space plus space 4 straight H subscript 2 straight O left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space Fe subscript 3 straight O subscript 4 left parenthesis straight s right parenthesis space plus space 4 straight H subscript 2 left parenthesis straight g right parenthesis
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70.

Write the expression for the equilibrium constant Kc for each of the following reactions:
space 2 NOCl left parenthesis straight g right parenthesis space space space space space space space space space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis

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