Find out the value of Kc for each of the following equilibria fr

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 Multiple Choice QuestionsLong Answer Type

131. Kp = 0·04 atm at 899 K for the equilibrium shown below. What is the equilibrium concentration of C2H6 when it is placed in a flask at 4·0 atm pressure and allowed to come to equilibrium?

            straight C subscript 2 straight H subscript 6 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space straight C subscript 2 straight H subscript 4 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
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132. A sample of pure PCl5 was introduced into an evacuated vessel at 473K. After equilibrium was attained, the concentration of PCl5 was found to be 0·5 × 10–1 mol L–1. If the value of Kc is 8·3 × 10–3, what are the concentrations of PCl3 and Cl2 at equilibrium?
                  PCl subscript 5 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space space PCl subscript 3 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis
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133. 3·00 mol of PCl5 kept in 1L closed reaction vessel was allowed to attain equilibrium at 380K. Calculate the composition of the mixture at equilibrium, Kc = 1·80.
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134.

Bromine monochloride (BrCl) decomposes into bromine and chlorine and attains the equilibrium:
space 2 BrCl space rightwards harpoon over leftwards harpoon space space space space Br subscript 2 left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis
for which Kc = 32 at 500 K. If initially pure BrCl is present at a concentration of 3·30×10–3 mol L–1 what is its molar concentration in the mixture at equilibrium?

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135. The value of Kc = 4·24 at 800 K for the reaction:
CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
Calculate equilibrium concentration of CO2, H2, CO and H2O at 800K, if only CO and H2O are present initially at concentrations of 0·10M each. 
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136. Dihydrogen gas used in Haber’s process is produced by reacting methane from natural gas with high temperature steam. The first stage of two stage reaction involves the formation of CO and H2. In second stage, CO formed in first stage is reacted with more steam in water gas shift reaction,
CO left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space CO subscript 2 left parenthesis straight g right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis
If a reaction vessel at 400°C is charged with an equimolar mixture of CO and steam such that pCO = 4·0 bar, what will be the partial pressure of H2 at equilibrium ? Kp = 10·1 at 400°C. 


 
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 Multiple Choice QuestionsShort Answer Type

137.

The value of increment straight G degree for the phoshorylation of glucose in glycolysis is 13.8 kJ/mol. Find the value of Kc at 298 K.

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138.

Hydrolysis of sucrose gives,
Sucrose space plus space straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon space space Glucose space plus space Fructose
Equilibrium constant Kc for the reaction is 2 cross times 10 to the power of 13 space at space 300 space straight K. Calculate increment straight G degree at 300K.

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 Multiple Choice QuestionsLong Answer Type

139. Calculate: (a) ∆G° and (b) the equilibrium constant for the formation of NO2from NO and O2 at 298 K.
     NO left parenthesis straight g right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis space space space leftwards harpoon over rightwards harpoon space space space NO subscript 2 left parenthesis straight g right parenthesis
where increment subscript straight f straight G to the power of 0 space left parenthesis NO subscript 2 right parenthesis space equals space 52.0 space kJ divided by mol comma space space increment subscript straight f straight G to the power of 0 left parenthesis NO right parenthesis space equals space 87.0 space kJ divided by mol comma space increment subscript straight f straight G to the power of 0 left parenthesis straight O subscript 2 right parenthesis space equals space 0 space kJ divided by mol.        
     
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 Multiple Choice QuestionsShort Answer Type

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140.

Find out the value of Kc for each of the following equilibria from the value of Kp:
2NOCl(g) rightwards harpoon over leftwards harpoon2NO(g) + Cl2(g);     Kp = 1.8 x 10-2 at 500 K


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