Write the correct balanced net ionic equation for the reaction whose equilibrium constant at 298K is:
(i) Ka(C6H5COOH) = 6·3 × 10–5
(ii) Ka(H2C2O4) = 5·4 × 10–2
(iii) Ka ( HSO3–) = 2·8 × 10–7
(iv) Kb(OCl–) = 9·1 × 10–7
Initial concentration of acetic acid = 0·1 M
As the degree of ionisation is 1·34% thus amount of acetic acid ionised
Thus we have,
CH3COOH CH3COO-(aq) + H3O+
Initial conc
0.1 M 0 0
Equilibrium conc
0.1 - 0.00134 0.00134 M 0.00134M
= 0.9866 M
Applying the law of chemical equilibrium,
Substituting the values, we have,